Regular Expression Matching 正则匹配问题
发布时间:2020-12-14 02:06:53 所属栏目:百科 来源:网络整理
导读:Implement regular expression matching with support for '.' and '*' . '.' Matches any single character.'*' Matches zero or more of the preceding element.The matching should cover the entire input string (not partial).The function prototype
Implement regular expression matching with support for '.' Matches any single character.
'*' Matches zero or more of the preceding element.
The matching should cover the entire input string (not partial).
The function prototype should be:
bool isMatch(const char *s,const char *p)
Some examples:
isMatch("aa","a") → false
isMatch("aa","aa") → true
isMatch("aaa","aa") → false
isMatch("aa","a*") → true
isMatch("aa",".*") → true
isMatch("ab",".*") → true
isMatch("aab","c*a*b") → true
class Solution { public: bool isMatch(const char *s,const char *p) { // Note: The Solution object is instantiated only once and is reused by each test case. if(p == NULL) return s!=NULL?false:true; if(*p == ' ') return *s == ' '; if(*(p+1) == '*') { while(*s==*p || (*p=='.' && (*s)!=' ') ) { if(isMatch(s,p+2) ) return true; ++s; } return isMatch(s,p+2); } else { if(*s==*p || (*p=='.'&&(*s)!=' ') ) return isMatch(s+1,p+1); else return false; } } }; 参考: http://www.52php.cn/article/p-vdzqmsnc-bap.html (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |