python 递归遍历文件夹,并打印满足条件的文件路径实例

#!/user/bin/env python
# -*- coding:utf-8 -*-

#grep -rl "python" D:devtoolsworkspacepythonaaa

import os

def init(func):
 def wrapper(*args,**kwargs):
  res=func(*args,**kwargs)
  res.send(None)
  return res
 return wrapper

@init
def search(target):
 '找到文件的绝对路径'
 while True:
  dir_name=yield
  g=os.walk(dir_name)
  for i in g:
   for j in i[-1]:
    file_path="%s%s"%(i[0],j)
    target.send(file_path)
@init
def get_file_handle(target):
 '获取文件句柄'
 while True:
  file_path=yield
  with open(file_path) as f:
   target.send((file_path,f))

@init
def cat_file(target):
 '读取文件'
 while True:
  file_path,f=yield
  for line in f:
   target.send((file_path,line))

@init
def printer(pattern):
 '打印满足过滤条件的文件'
 s=set()
 while True:
  file_path,line=yield
  if pattern in line:
   if file_path not in s:
    print(file_path)
   s.add(file_path)


g=search(get_file_handle(cat_file(printer("python"))))
g.send("D:devtoolsworkspacepythonaaa")