java – 使用OAuth-Signpost和Apache HttpComponents签署POST请

我正在使用OAuth-Signpost Java库来签署从客户端发送到实现OAuth身份验证的服务器的请求.当GET请求(使用HttpURLConnection)时,一切都正常：请求被签名,参数被包括,签名在目的地匹配.但是,它似乎不适用于POST请求.我知道在使用HttpURLConnection签名POST时可能出现的问题,所以我转移到Apache HttpComponents库以获得这些请求.在以下示例中发送的参数是纯字符串和类似XML的字符串(“rxml”).我的代码如下：

public Response exampleMethod(String user,String sp,String ep,String rn,String rxml){

   //All these variables are proved to be correct (they work right in GET requests)
    String uri = "...";
    String consumerKey = "...";
    String consumerSecret = "...";
    String token = "...";
    String secret = "...";

  //create the parameters list
    List<NameValuePair> params = new ArrayList<NameValuePair>();
    params.add(new BasicNameValuePair("user",user));
    params.add(new BasicNameValuePair("sp",sp));
    params.add(new BasicNameValuePair("ep",ep));
    params.add(new BasicNameValuePair("rn",rn));
    params.add(new BasicNameValuePair("rxml",rxml));

   // create a consumer object and configure it with the access
   // token and token secret obtained from the service provider
    OAuthConsumer consumer = new CommonsHttpOAuthConsumer(consumerKey,consumerSecret);
    consumer.setTokenWithSecret(token,secret);

   // create an HTTP request to a protected resource
    HttpPost request = new HttpPost(uri);

   // sign the request      
    consumer.sign(request);       

   // set the parameters into the request
    request.setEntity(new UrlEncodedFormEntity(params));

   // send the request
    HttpClient httpClient = new DefaultHttpClient();
    HttpResponse response = httpClient.execute(request);

   //if request was unsuccessful
    if(response.getStatusLine().getStatusCode()!=200){
        return Response.status(response.getStatusLine().getStatusCode()).build();
    }

   //if successful,return the response body
    HttpEntity resEntity = response.getEntity();
    String responseBody = "";

    if (resEntity != null) {
        responseBody = EntityUtils.toString(resEntity);
    }

    EntityUtils.consume(resEntity);

    httpClient.getConnectionManager().shutdown();

    return Response.status(200).entity(responseBody).build();

}

当我向服务器发送POST请求时,我得到一个错误,告诉我签名(我发送的一个和服务器自己计算的一个)不匹配,所以我想这与签名的基本字符串有关以及POST签名的工作方式,因为它们正在处理双方的密钥和秘密(已选中).

我已经看到,通过这种方式将参数设置为URL的一部分(如在GET请求中).这对我来说不行,因为XML参数可能会超过URL长度,因此需要作为POST参数发送.

我想我在签名POST请求或处理参数时出错了,但我不知道是什么.请你帮帮我吗

P.S：如果我缺乏关于这个问题的上下文,错误跟踪或其他信息,我很抱歉,但我在这里是新手.所以请不要犹豫,要求我更多的信息,如果你需要它.

public void setMethod(String method){
try {
 this.connection.setRequestMethod(method);
 } catch (ProtocolException e) {

    e.printStackTrace();
 }
}

public void setMethod(String method){

   try {
       RequestWrapper wrapper = new RequestWrapper(this.request);
       wrapper.setMethod(method);
       request = wrapper;
   } catch (org.apache.http.ProtocolException e) {
    e.printStackTrace();
    }   
}

public void setMethod(String method){
   mMethod = method;
}