groovy – 让Jenkins上游工作

发布时间：2020-12-14 16:36:10 所属栏目：大数据来源：网络整理

导读：我想获得所有上游作业,就像在控制台输出中一样： Started by upstream project "allocate" build number 31originally caused by: Started by upstream project "start" build number 12originally caused by: 我尝试了groovy postbuild与以下内容： def bui

我想获得所有上游作业,就像在控制台输出中一样：

Started by upstream project "allocate" build number 31
originally caused by: 
Started by upstream project "start" build number 12
originally caused by:

我尝试了groovy postbuild与以下内容：

def build = Thread.currentThread().executable
def causes= manager.build.getCauses()
for (cause in causes)
{
manager.listener.logger.println "upstream build: " + cause.getShortDescription()

}

但后来我只得到“分配”,而不是“开始”工作.

我也试过了

def build = Thread.currentThread().executable
def test = build.getUpstreamBuilds()
for (up in test)
{
manager.listener.logger.println "test build project: " + up
}

但这是空的……

有任何想法吗？

解决方法

您接近第一个解决方案.

实际上,你需要做的是根据它的类型迭代这个原因的祖先.

以下是可以帮助您入门的示例代码段：

def printCausesRecursively(cause) {
     if (cause.class.toString().contains("UpstreamCause")) {
         println "This job was caused by " + cause.toString()
         for (upCause in cause.upstreamCauses) {
             printCausesRecursively(upCause)
         }
     } else {
         println "Root cause : " + cause.toString()
     }
}

for (cause in manager.build.causes)
{
    printCausesRecursively(cause)
}

您可能需要参考文档来处理所有原因类型：http://javadoc.jenkins-ci.org/hudson/model/Cause.html

希望能帮助到你,

最好

（编辑：李大同）

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