108. Convert Sorted Array to Binary Search Tree
发布时间:2020-12-14 04:38:02 所属栏目:大数据 来源:网络整理
导读:Given an array where elements are sorted in ascending order,convert it to a height balanced BST. For this problem,a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of? every ?node never differ
Given an array where elements are sorted in ascending order,convert it to a height balanced BST. For this problem,a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of?every?node never differ by more than 1. Example: Given the sorted array: [-10,-3,5,9],One possible answer is: [0,9,-10,null,5],which represents the following height balanced BST: 0 / -3 9 / / -10 5 class Solution { public TreeNode sortedArrayToBST(int[] nums) { if(nums.length == 0) return null; return help(nums,nums.length - 1); } public TreeNode help(int[] nums,int start,int end){ int l = end - start; if(l < 0) return null; int mid = (start + end) / 2; TreeNode root = new TreeNode(nums[mid]); root.left = help(nums,start,mid - 1); root.right = help(nums,mid+1,end); return root; } } 没什么特殊的,每一步都是把中间的当作root,然后两边作为subtree。 (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |