HDU-1042(大数阶乘_java)
发布时间:2020-12-14 04:12:37 所属栏目:大数据 来源:网络整理
导读:N! Time Limit: 10000/5000 MS (Java/Others)????Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 40878????Accepted Submission(s): 11339 Problem Description Given an integer N(0 ≤ N ≤ 10000),your task is to calculate N! ? Inpu
N!Time Limit: 10000/5000 MS (Java/Others)????Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 40878????Accepted Submission(s): 11339
Problem Description
Given an integer N(0 ≤ N ≤ 10000),your task is to calculate N!
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Input
One N in one line,process to the end of file.
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Output
For each N,output N! in one line.
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Sample Input
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Sample Output
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Author
JGShining(极光炫影)
呼呼,还是要把java练一练那,如果练好了,真是事半功倍呀,而且一定要把java学精通那,.,要不然,自己写高精度可就累死了,而且随着科技的发展,java能够脱颖而出是有它的道理的, 贴出我的N!的java代码:
import java.util.Scanner;//这是输入必须要引入的类 import java.math.BigInteger;//这是利用大数必须要用的类 /* *传说中的大数精度,用java一下子就解决了,我表示很无语,*但是如果你没有写过的话,还是写不出来的. *肯定是要多练习的 */ public class Main { public static void main (String[] args) { Scanner input = new Scanner(System.in); BigInteger a;//声明一个大数的引用a a = BigInteger.valueOf(1);//这个valueOf可以将int,long,str顺利转变成BigInteger类型; int N; while (input.hasNext())//input.hasNext()就相当于!= EOF { N = input.nextInt(); for (int i = 1; i <= N; i++) { a = a.multiply(BigInteger.valueOf(i));//将整型的数转换成BigInteger; } System.out.println (a); a = BigInteger.valueOf(1);//记住每次都要把a转置成1; } } } (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |