vb.net – 从数组中删除最后一个元素
发布时间:2020-12-17 07:26:25 所属栏目:百科 来源:网络整理
导读:如何从VB.NET中删除数组中的最后一个元素.我需要分开街道和房子. 街 拆分空格上的地址 删除最后一个元素(代码中缺少) 加入数组 数 拆分空格上的地址 获取最后一个元素 我的代码: 'split addressDim addressArray() As String = args.Content.Split(" ")'rem
如何从VB.NET中删除数组中的最后一个元素.我需要分开街道和房子.
街 >拆分空格上的地址 数 >拆分空格上的地址 我的代码: 'split address Dim addressArray() As String = args.Content.Split(" ") 'remove last element and return the joined array Return String.Join(" ",addressArray.Remove(addressArray.Length() - 1)) 解决方法Dim foo() As String = "This is a test".Split(New Char() {" "c},StringSplitOptions.RemoveEmptyEntries) Array.Resize(foo,foo.Length - 1) Dim s As String = String.Join(" ",foo) 或使用清单 Dim foo As New List(Of String) foo.AddRange("This is a test".Split(New Char() {" "c},StringSplitOptions.RemoveEmptyEntries)) foo.RemoveAt(foo.Count - 1) Dim s As String = String.Join(" ",foo) 至于使用LINQ和性能,自己判断 Public Class Form1 'to LINQ or not to LINQ 'judge for yourself Dim stpw As New Stopwatch Private Sub Button1_Click(sender As System.Object,_ e As System.EventArgs) Handles Button1.Click Dim ipsumA() As String = New String() {"Lorem","ipsum","dolor","sit",_ "amet","consectetur","adipisicing",_ "elit","sed","do","eiusmod",_ "tempor","incididunt","ut","labore",_ "et","dolore","magna","aliqua","Ut",_ "enim","ad","minim","veniam","quis",_ "nostrud","exercitation","ullamco",_ "laboris","nisi","aliquip","ex",_ "ea","commodo","consequat","Duis","aute",_ "irure","in","reprehenderit",_ "voluptate","velit","esse","cillum",_ "eu","fugiat","nulla","pariatur","Excepteur",_ "sint","occaecat","cupidatat","non","proident",_ "sunt","culpa","qui","officia","deserunt",_ "mollit","anim","id","est","laborum"} Const tries As Integer = 100000 Debug.WriteLine("") stpw.Reset() stpw.Start() For x As Integer = 1 To tries Dim s As String = arrayTake(ipsumA) Next stpw.Stop() Debug.WriteLine(stpw.ElapsedTicks.ToString) stpw.Reset() stpw.Start() For x As Integer = 1 To tries Dim s As String = arrayRsz(ipsumA) Next stpw.Stop() Debug.WriteLine(stpw.ElapsedTicks.ToString) End Sub Private Function arrayRsz(test As String()) As String Array.Resize(test,test.Length - 1) Return String.Join(" ",test) End Function Private Function arrayTake(test As String()) As String Return String.Join(" ",test.Take(test.Length - 1)) End Function End Class (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |