在单个foreach C#中迭代2个形状列表

发布时间：2020-12-15 22:41:32 所属栏目：百科来源：网络整理

导读：我有两个shapeIds列表来自2个单独的PowerPoint演示文稿,一个来自原始PowerPoint,另一个来自编辑过的PowerPoint. 我现在想要将这两个列表中的项目ShapeId相互比较.例如,我想比较颜色和字体大小等. 我已经尝试了很多方法来做到这一点,并决定迭代2个列表中的每

我有两个shapeIds列表来自2个单独的PowerPoint演示文稿,一个来自原始PowerPoint,另一个来自编辑过的PowerPoint.

我现在想要将这两个列表中的项目ShapeId相互比较.例如,我想比较颜色和字体大小等.

我已经尝试了很多方法来做到这一点,并决定迭代2个列表中的每个ShapeId的最佳方法.无论如何我可以在一个foreach循环中迭代每个列表吗？例如foreach(list1中的Microsoft.Office.Interop.PowerPoint.Slide幻灯片item1,list2中的Microsoft.Office.Interop.PowerPoint.Slide幻灯片item2)

我的代码就像休耕一样

Microsoft.Office.Interop.PowerPoint.CustomLayout customLayout = pptPresentationOriginal.SlideMaster.CustomLayouts[Microsoft.Office.Interop.PowerPoint.PpSlideLayout.ppLayoutText];
    Microsoft.Office.Interop.PowerPoint.Slides Originalslides;
    Microsoft.Office.Interop.PowerPoint.Slides EditedSlides;
    Microsoft.Office.Interop.PowerPoint.Shape originalShp;
    Microsoft.Office.Interop.PowerPoint.Shape editShp;
    Originalslides = pptPresentationOriginal.Slides;
    EditedSlides = pptPresentationEdit.Slides;
    List<char> l = new List<char>();
    List<char> l2 = new List<char>();
    List<int> originalShapesListID = new List<int>();
    List<int> editedShapesListID = new List<int>();
    List<int> originalListID = new List<int>();
    List<int> editedListID = new List<int>();
    List<Microsoft.Office.Interop.PowerPoint.Shape> originalList = new List<Microsoft.Office.Interop.PowerPoint.Shape>();
    List<Microsoft.Office.Interop.PowerPoint.Shape> editList = new List<Microsoft.Office.Interop.PowerPoint.Shape>();
    Microsoft.Office.Interop.PowerPoint.Shape editedShpID;

逻辑

String pps = "";

    foreach (Microsoft.Office.Interop.PowerPoint.Slide slide in Originalslides)
    {
        foreach (Microsoft.Office.Interop.PowerPoint.Shape originalShape in slide.Shapes)
        {
            originalShp = originalShape;
            if (originalShape.HasTextFrame == Microsoft.Office.Core.MsoTriState.msoTrue)
            {
                var textFrame = originalShape.TextFrame;
                if (textFrame.HasText == Microsoft.Office.Core.MsoTriState.msoTrue)
                {
                    var textRange = textFrame.TextRange;
                    pps += originalShape.TextFrame.TextRange.Text;
                    foreach (char word in pps)
                    {

                        l.Add(word);
                        Debug.WriteLine(word);
                    }

                }
            }
            originalShapesListID.Add(originalShape.Id);
            originalShapeID = originalShape.Id;
            originalList.Add(originalShape);
        }

        originalListID.Add(slide.SlideID);
    }

    foreach (Microsoft.Office.Interop.PowerPoint.Slide slide in EditedSlides)
    {
        foreach (Microsoft.Office.Interop.PowerPoint.Shape editShape in slide.Shapes)
        {
            editShp = editShape;
            if (editShape.HasTextFrame == Microsoft.Office.Core.MsoTriState.msoTrue)
            {

                var textFrame = editShape.TextFrame;
                if (textFrame.HasText == Microsoft.Office.Core.MsoTriState.msoTrue)
                {
                    var textRange = textFrame.TextRange;
                    pps += editShape.TextFrame.TextRange.Text;
                    foreach (char word in pps)
                    {
                        l.Add(word);
                        Debug.WriteLine(word);
                    }
                }
            }

            editedShapesListID.Add(editShape.Id);
            editedShapeID = editShape.Id;
            editList.Add(editShape);




        }

        editedListID.Add(slide.SlideID);


    }

这是我想要浏览2个列表并比较每个列表中的每个项目(ShapeId)的地方.我想做这样的事情.

foreach (Microsoft.Office.Interop.PowerPoint.Shape editShape in editedShapesListID,Microsoft.Office.Interop.PowerPoint.Shape original in originalShapesListID )
    {

        if (originalShapeID == editedShapeID)
        {


            if (original.TextFrame.TextRange.Font.Color.RGB != editShape.TextFrame.TextRange.Font.Color.RGB)
            {
                originalShp.TextFrame2.TextRange.Font.StrikeThrough.ToString();
            }
        }
    }

解决方法

由于您希望匹配特定密钥ID上的项目.一个很好的选择是使用连接. Join将为内部集合构建一个哈希表,该哈希表具有O(1)查找.

var q = from original in originalShapes
        join editedTmp in editedShapes on original.Id equals editedTmp.Id into g
        from edited in g.DefaultIfEmpty()
        select new
        {
           original,edited
        };

foreach(var item in q)
{
    //item.edited might be null if no matching original was found.
    if (item.edited == null || item.original.TextFrame.TextRange.Font.Color.RGB != item.edited.TextFrame.TextRange.Font.Color.RGB)
    {
       item.original.TextFrame2.TextRange.Font.StrikeThrough.ToString();
    }
}

（编辑：李大同）

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