使用json.NET和C#解析JSON数组
发布时间:2020-12-16 18:40:33 所属栏目:百科 来源:网络整理
导读:我有一些我需要解析的以下 JSON格式的数据: {"status":0,"timestamp":"8:20pm","routes":[ { "directions":[ "E Towne","ETP" ],"routeID":"30" },{ "directions":[ "Johnson","Observatory" ],"routeID":"81" }]} 使用json.net,我想得到以下输出: 30 E To
我有一些我需要解析的以下
JSON格式的数据:
{ "status":0,"timestamp":"8:20pm","routes":[ { "directions":[ "E Towne","ETP" ],"routeID":"30" },{ "directions":[ "Johnson","Observatory" ],"routeID":"81" } ] } 使用json.net,我想得到以下输出:
使用下面的代码,我得到以下不正确的输出:
如何将方向数组项写入相应的routeID项?我的代码: public class Route { public string routeID { get; set; } public string directions { get; set; } } private void routeClient_DownloadStringCompleted(object sender,DownloadStringCompletedEventArgs e) { string jsonResults_routes = e.Result; JObject routeData = JObject.Parse(jsonResults_routes); JArray routeIdArray = (JArray)routeData["routes"]; JArray routeDirections = (JArray)routeData["routes"][0]["directions"]; List<Route> l = new List<Route>(); for (int i = 0; i < routeIdArray.Count; i++) { Route BusRoutes = new Route(); JObject routeIDarrayObject = (JObject)routeIdArray[i]; BusRoutes.routeID = (string)routeIDarrayObject["routeID"]; string sep = " - "; string bothDirections = String.Join(sep,routeDirections); List<string> sc = new List<string>(); string[] direction = new string[]{bothDirections}; sc.AddRange(direction); foreach (string direx in sc) { BusRoutes.directions = direx; } l.Add(BusRoutes); } var newList = l.OrderBy(x => x.routeID).ToList(); lbRoutesData.ItemsSource = newList; } 解决方法
@competent_tech在分析中是正确的.如果我可以提出建议,我认为如果你使用实际物体会更自然.例如:
public class RouteInfo { public List<string> Directions { get; set; } public string RouteID { get; set; } } public class RouteData { public int Status { get; set; } public string Timestamp { get; set; } public List<RouteInfo> Routes { get; set; } } 在你的方法中: var routeData = JsonConvert.DeserializeObject<RouteData>(e.Result); return routeData.Routes .Select(r => new Route { routeId = r.RouteID,directions = String.Join(" - ",r.Directions) }) .OrderBy(r =-> r.routeId) .ToList(); 或者更自然地以其他方式操纵您的类型对象. 编辑:要获得基于JSON字符串生成类的简单方法,请转到json2csharp. (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |