c# – Dictionary ToList序列化的问题

我尝试使用ToList选项序列化字典的值.
我发现在deserializtion过程中,我对所有序列化的对象都获取了null
当我使用内存流时它没有发生,当我使用.Net对象作为字典中的类型时没有发生.
下面是我创建的示例代码,用于显示问题
这段代码的输出是
字典：0-0
字典：1-1
清单：0
清单：1
字典：0-Null
字典：1-Null
清单：0

class Program
{
    static void Main(string[] args)
    {
        A state = new A();

        Stream stream = File.Open("D:temptemp.txt",FileMode.Create);
        BinaryFormatter bFormatter = new BinaryFormatter();
        bFormatter.Serialize(stream,state);
        stream.Close();

        state.PrintData();

        stream = File.Open("D:temptemp.txt",FileMode.Open);
        bFormatter = new BinaryFormatter();
        state = (A)bFormatter.Deserialize(stream);
        stream.Close();

        state.PrintData();
    }
}

[Serializable()]
public class A : ISerializable
{
    Dictionary<int,B> dic = new Dictionary<int,B>();
    List<B> list = new List<B>();

    public A()
    {
        for (int i = 0; i < 4; i++)
        {
            dic.Add(i,new B(i));
            list.Add(new B(i));
        }
    }

    public void PrintData()
    {
        foreach (KeyValuePair<int,B> kvp in dic)
        {
            Console.WriteLine("Dictionary: " + kvp.Key.ToString() + "-" + ((kvp.Value != null) ? kvp.Value.ToString() : "Null"));
        }
        foreach(B b in list)
        {
            Console.WriteLine("List: " + b.ToString());
        }
    }

    public A(SerializationInfo info,StreamingContext context)
    {
        List<int> keys = info.GetValue("keys",typeof(List<int>)) as List<int>;
        List<B> values = info.GetValue("values",typeof(List<B>)) as List<B>;

        int count = keys.Count;
        if(count == values.Count)
        {
            for(int i = 0; i < count; i++)
            {
                dic[keys[i]] = values[i];
            }
        }

        list = info.GetValue("list",typeof(List<B>)) as List<B>;
    }

    public void GetObjectData(SerializationInfo info,StreamingContext context)
    {
        info.AddValue("keys",dic.Keys.ToList(),typeof(List<int>));
        info.AddValue("values",dic.Values.ToList(),typeof(List<B>));
        List<B> listFromDic = new List<B>(dic.Values.ToList());
        info.AddValue("list",listFromDic,typeof(List<B>));
    }
}

[Serializable()]
public class B : ISerializable
{
    int foo;

    public B(int i)
    {
        foo = i;
    }

    public B(SerializationInfo info,StreamingContext context)
    {
        foo = info.GetInt32("foo");
    }

    public void GetObjectData(SerializationInfo info,StreamingContext context)
    {
        info.AddValue("foo",foo);
    }

    public override string ToString()
    {
        return (foo != null) ? foo.ToString() : String.Empty;
    }
}

public A(SerializationInfo info,StreamingContext context)
    {
        dic = info.GetValue("mapping",typeof(Dictionary<int,B>)) as Dictionary<int,B>;
        list = info.GetValue("list",StreamingContext context)
    {
        info.AddValue("mapping",dic,B>));
        List<B> listFromDic = new List<B>(dic.Values.ToList());
        info.AddValue("list",typeof(List<B>));
    }

[Serializable()]
public class A : ISerializable,IDeserializationCallback 
{
    Dictionary<int,B>();
    List<B> list = new List<B>();
    private List<int> keys = new List<int>();

    public A()
    {
        for (int i = 0; i < 4; i++)
        {
            dic.Add(i,B> kvp in dic)
        {
            Console.WriteLine("Dictionary: " + kvp.Key.ToString() + "-" + ((kvp.Value != null) ? kvp.Value.ToString() : "Null"));
        }
        foreach (B b in list)
        {
            Console.WriteLine("List: " + b.ToString());
        }
    }

    public A(SerializationInfo info,StreamingContext context)
    {
        keys = info.GetValue("keys",typeof(List<B>)) as List<B>;

        list = info.GetValue("list",typeof(List<B>));
    }

    public void OnDeserialization(object sender)
    {
        dic = new Dictionary<int,B>();
        int count = keys.Count;
        if (count == list.Count)
        {
            for (int i = 0; i < count; i++)
            {
                dic[keys[i]] = list[i];
            }
        }
    }
}