Flex日期操作之二( 获取昨天的日期)
发布时间:2020-12-15 05:12:42 所属栏目:百科 来源:网络整理
导读:有一项目碰到在Flex中求昨天的日期,由于之前在C#中接触过这种情况: ?//计算昨天日期 string strYersterday = DateTime.Now.AddDays(-1).ToString("yyyy-MM-dd"); 接触Flex时间不长不知道有没有这种方法,最后采用了一种比较原始的计算方法,总觉得洛里啰嗦
有一项目碰到在Flex中求昨天的日期,由于之前在C#中接触过这种情况: ?//计算昨天日期 接触Flex时间不长不知道有没有这种方法,最后采用了一种比较原始的计算方法,总觉得洛里啰嗦的 private function getYearMonDay(date:Date):String { var strYMD:String; var strMon:String; var strDay:String; if(date == null) { strYMD = "2020/12/31"; } else { if((date.getMonth()+1)<10) { strMon = "0" + (date.getMonth()+1).toString(); if((date.getDate()-1)<10 &&(date.getDate()-1)>0) strDay = "0" + (date.getDate()-1).toString(); else if(date.getDate() - 1 == 0) { switch(strMon) { case "01": strDay = "31"; strMon = "12"; break; case "02": strDay = "31"; strMon = "01"; break; case "03": strDay = "28"; strMon = "02"; break; case "04": strDay = "31"; strMon = "03"; break; case "05": strDay ="30"; strMon = "04"; break; case "06": strDay = "31"; strMon = "05"; break; case "07": strDay = "30"; strMon = "06"; break; case "08": strDay = "31"; strMon = "07"; break; case "09": strDay = "31"; strMon = "08"; break; case "10": strDay = "30"; strMon = "09"; break; case "11": strDay = "31"; strMon ="10"; break; case "12": strDay ="30"; strMon = "11"; break; } } else strDay = (date.getDate()-1).toString(); } else { strMon = (date.getMonth()+1).toString(); if((date.getDate()-1)<10 &&(date.getDate()-1)>0) strDay = "0" + (date.getDate()-1).toString(); else if(date.getDate() - 1 == 0) { switch(strMon) { case "01": strDay = "31"; strMon = "12"; break; case "02": strDay = "31"; strMon = "01"; break; case "03": strDay = "28"; strMon = "02"; break; case "04": strDay = "31"; strMon = "03"; break; case "05": strDay ="30"; strMon = "04"; break; case "06": strDay = "31"; strMon = "05"; break; case "07": strDay = "30"; strMon = "06"; break; case "08": strDay = "31"; strMon = "07"; break; case "09": strDay = "31"; strMon = "08"; break; case "10": strDay = "30"; strMon = "09"; break; case "11": strDay = "31"; strMon ="10"; break; case "12": strDay ="30"; strMon = "11"; break; } } else strDay = (date.getDate()-1).toString(); } strYMD = date.getFullYear().toString()+"/"+strMon+"/"+ strDay; } return strYMD; }(编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |