c# – 将中值方法添加到列表
发布时间:2020-12-15 06:24:49 所属栏目:百科 来源:网络整理
导读:我想覆盖C#中的List对象,以便添加一个中值方法,如Sum或Average.我已经发现这个功能: public static decimal GetMedian(int[] array){ int[] tempArray = array; int count = tempArray.Length; Array.Sort(tempArray); decimal medianValue = 0; if (count
我想覆盖C#中的List对象,以便添加一个中值方法,如Sum或Average.我已经发现这个功能:
public static decimal GetMedian(int[] array) { int[] tempArray = array; int count = tempArray.Length; Array.Sort(tempArray); decimal medianValue = 0; if (count % 2 == 0) { // count is even,need to get the middle two elements,add them together,then divide by 2 int middleElement1 = tempArray[(count / 2) - 1]; int middleElement2 = tempArray[(count / 2)]; medianValue = (middleElement1 + middleElement2) / 2; } else { // count is odd,simply get the middle element. medianValue = tempArray[(count / 2)]; } return medianValue; } 你能告诉我怎么做吗 解决方法
使用扩展方法,并复制输入的数组/列表.
public static decimal GetMedian(this IEnumerable<int> source) { // Create a copy of the input,and sort the copy int[] temp = source.ToArray(); Array.Sort(temp); int count = temp.Length; if (count == 0) { throw new InvalidOperationException("Empty collection"); } else if (count % 2 == 0) { // count is even,average two middle elements int a = temp[count / 2 - 1]; int b = temp[count / 2]; return (a + b) / 2m; } else { // count is odd,return the middle element return temp[count / 2]; } } (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |