正则表达式将字词与唯一(不重复)字符进行匹配

发布时间：2020-12-14 06:32:52 所属栏目：百科来源：网络整理

导读：我正在寻找一个正则表达式，只有当它的所有字符都是唯一的，这意味着该单词中的每个字符才会出现一次。例： abcdefg – 将返回MATCH abcdefgbh – 将返回NO MATCH(因为字母b重复多次) 尝试这个，可能会工作， ^(?:([A-Za-z])(?!.*1))*$ 说明 Assert positi

我正在寻找一个正则表达式，只有当它的所有字符都是唯一的，这意味着该单词中的每个字符才会出现一次。

例：
abcdefg – >将返回MATCH
abcdefgbh – >将返回NO MATCH(因为字母b重复多次)

尝试这个，可能会工作，

^(?:([A-Za-z])(?!.*1))*$

说明

Assert position at the beginning of a line (at beginning of the string or after a line break character) ?^?
Match the regular expression below ?(?:([A-Z])(?!.*1))*?
   Between zero and unlimited times,as many times as possible,giving back as needed (greedy) ?*?
   Match the regular expression below and capture its match into backreference number 1 ?([A-Z])?
      Match a single character in the range between “A” and “Z” ?[A-Z]?
   Assert that it is impossible to match the regex below starting at this position (negative lookahead) ?(?!.*1)?
      Match any single character that is not a line break character ?.*?
         Between zero and unlimited times,giving back as needed (greedy) ?*?
      Match the same text as most recently matched by capturing group number 1 ?1?
Assert position at the end of a line (at the end of the string or before a line break character) ?$?

（编辑：李大同）

【声明】本站内容均来自网络，其相关言论仅代表作者个人观点，不代表本站立场。若无意侵犯到您的权利，请及时与联系站长删除相关内容!