正则表达式:6位数或0-6个符号(数字或星号),至少有一颗星
发布时间:2020-12-14 06:06:29 所属栏目:百科 来源:网络整理
导读:如何编写正则表达式来验证这种模式? 123456 - correct*1 - correct1* - correct124** - correct*1*2 - correct* - correct123456* - incorrect (size 7)12345 - incorrect (size 5 without stars) 尝试: ^[0-9]{6}$|^(([0-9]){1,6}([*]){1,5}){1,6}+$ 但它
如何编写正则表达式来验证这种模式?
123456 - correct *1 - correct 1* - correct 124** - correct *1*2 - correct * - correct 123456* - incorrect (size 7) 12345 - incorrect (size 5 without stars) 尝试: ^[0-9]{6}$|^(([0-9]){1,6}([*]){1,5}){1,6}+$ 但它允许有超过6个数字,并且不允许星号在数字之前. 解决方法
干得好:
^(?:d{6}|(?=.**)[d*]{1,6}|)$ 这是它的作用: ^ <-- Start of the string (we don't want to capture more than that) (?: <-- Start a non captured group (it will be used to do the "or" part) d{6} <-- 6 digits,nothing more | <-- OR (?=.**) <-- Look ahead for a '*' (you could replace the first * with {0,5}) [d*] <-- digits or '*' {1,6} <-- repeated one to six times (we know from the look ahead that there will be at least one '*' | <-- OR (nothing) ) <-- End the non capturing group $ <-- End of the string 我不太确定你是否想要空的情况(但你说的是0到6),如果你真的想要1到6只是删除最后一个| (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |