‘DispatchQueue’类型的值没有成员’异步’ – Swift 3
发布时间:2020-12-14 05:25:59 所属栏目:百科 来源:网络整理
导读:我刚刚将 xcode8更新为 Swift 3并收到此错误: Value of type 'DispatchQueue' has no member 'asynchronously' 在这条线上: DispatchQueue.main.asynchronously(execute: 这是整个代码段: DispatchQueue.main.asynchronously(execute: { //Display alert
我刚刚将
xcode8更新为
Swift 3并收到此错误:
Value of type 'DispatchQueue' has no member 'asynchronously' 在这条线上: DispatchQueue.main.asynchronously(execute: 这是整个代码段: DispatchQueue.main.asynchronously(execute: { //Display alert message with confirmation let myAlert = UIAlertController(title: "Alert",message:messageToDisplay,preferredStyle: UIAlertControllerStyle.Alert); let okAction = UIAlertAction(title:"OK",style:UIAlertActionStyle.Default){ action in self.dismissViewControllerAnimated(true,completion:nil); } myAlert.addAction(okAction) self.presentViewController(myAlert,animated:true,completion:nil); }); } } catch let error as NSError { print(error.localizedDescription) } } task.resume() } } 最近更新到Swift 3给了我很多错误,它们会自动修复,但是这个不会自行解决,我不知道该怎么做.
在Swift 3和iOS 10的生产版本中,没有异步方法.这只是异步:
DispatchQueue.main.async { //Display alert message with confirmation let alert = UIAlertController(title: "Alert",message: messageToDisplay,preferredStyle: .alert) let okAction = UIAlertAction(title: "OK",style: .default) { action in self.dismiss(animated: true) } alert.addAction(okAction) self.present(alert,animated: true) } (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |