如何在IE上修复twitter-bootstrap?
发布时间:2020-12-18 00:00:59 所属栏目:安全 来源:网络整理
导读:导航栏似乎没有在IE中正常工作。这里是它在IE中的屏幕截图。 我一直在通过许多bootstrap主题在stackoverflow.com,但他们给人们的“帮助”不适合我。 后身体标签: div class="container" div class="navbar navbar-fixed-top" div class="navbar-inner" div
导航栏似乎没有在IE中正常工作。这里是它在IE中的屏幕截图。
我一直在通过许多bootstrap主题在stackoverflow.com,但他们给人们的“帮助”不适合我。 后身体标签: <div class="container"> <div class="navbar navbar-fixed-top"> <div class="navbar-inner"> <div class="container"> <a class="brand" href="?id=home">OnniServer.tk</a> <div class="nav-collapse"> <ul class="nav"> <li <?php if ((isset($_GET['id'])) && ($_GET['id'] == home)) { echo "class='active'"; } ?>><a href="?id=home">Home</a></li> <li <?php if ((isset($_GET['id'])) && ($_GET['id'] == donate)) { echo "class='active'"; } ?>><a href="?id=donate">Donate</a></li> <li <?php if ((isset($_GET['id'])) && ($_GET['id'] == about)) { echo "class='active'"; } ?>><a href="?id=about">About</a></li> <li <?php if ((isset($_GET['id'])) && ($_GET['id'] == staff)) { echo "class='active'"; } ?>><a href="?id=staff">Staff</a></li> <li <?php if ((isset($_GET['id'])) && ($_GET['id'] == vote)) { echo "class='active'"; } ?>><a href="?id=vote">Vote</a></li> <li class="dropdown"> <a href="" class="dropdown-toggle" data-toggle="dropdown">Play now: <b class="caret"></b></a> <ul class="dropdown-menu"> <li><a href="minecraft">In browser</a></li> <li><a href="http://minecraft.net">Buy it now</a></li> <li><a href="#">No link for crack</a></li> </ul> </li> <li class="dropdown"> <a href="" class="dropdown-toggle" data-toggle="dropdown">Perms for: <b class="caret"></b></a> <ul class="dropdown-menu"> <li><a href="?id=citizen">Citizen(s)</a></li> <li><a href="?id=vip">VIP(s)</a></li> <li><a href="?id=vipplus">VIP+(s)</a></li> <li><a href="?id=modjr">Jr. Moderator(s)</a></li> <li><a href="?id=mod">Moderator(s)</a></li> <li><a href="?id=admin">Admin(s)</a></li> <li><a href="?id=owner">Owner</a></li> </ul> </li> <li class="dropdown"> <a href="" class="dropdown-toggle" data-toggle="dropdown">Mail to: <b class="caret"></b></a> <ul class="dropdown-menu"> <li><a href="mailto:onni.bucht@me.com">Onni (server Owner)</a></li> </ul> </li> <script> $('.dropdown-toggle').dropdown() </script> </ul> </div> </div> </div> </div> <p> </p> <p> </p> <div class="hero-unit"> <style "text/css"> </style> <?php if (((isset($_GET['id'])) &&($_GET['id'] == home)) || (!isset($_GET['id']))) { include('home.php'); }; if ((isset($_GET['id'])) && ($_GET['id'] == donate)) { include('donate.php'); }; if ((isset($_GET['id'])) && ($_GET['id'] == about)) { include('about.php'); }; if ((isset($_GET['id'])) && ($_GET['id'] == staff)) { include('staff.php'); }; if ((isset($_GET['id'])) && ($_GET['id'] == vote)) { include('vote.php'); }; if ((isset($_GET['id'])) && ($_GET['id'] == citizen)) { include('permissions/citizen.html'); }; if ((isset($_GET['id'])) && ($_GET['id'] == vip)) { include('permissions/vip.html'); }; if ((isset($_GET['id'])) && ($_GET['id'] == vipplus)) { include('permissions/vipplus.html'); }; if ((isset($_GET['id'])) && ($_GET['id'] == modjr)) { include('permissions/modjr.html'); }; if ((isset($_GET['id'])) && ($_GET['id'] == mod)) { include('permissions/mod.html'); }; if ((isset($_GET['id'])) && ($_GET['id'] == admin)) { include('permissions/admin.html'); }; if ((isset($_GET['id'])) && ($_GET['id'] == owner)) { include('permissions/owner.html'); }; ?> </div> </div> 解决方法
您需要将<!DOCTYPE HTML>在你的html的第一行。
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