angular – typescript函数返回undefined
发布时间:2020-12-17 07:56:00 所属栏目:安全 来源:网络整理
导读:您好,我在下面的课程中有一个方法: export class SearchService { userUID: string; searchItems: any; private searchesCollection: AngularFirestoreCollection; constructor( private db: AngularFirestore,private afAuth: AngularFireAuth,) { } getSe
您好,我在下面的课程中有一个方法:
export class SearchService { userUID: string; searchItems: any; private searchesCollection: AngularFirestoreCollection; constructor( private db: AngularFirestore,private afAuth: AngularFireAuth,) { } getSearches() { this.afAuth.authState.subscribe(user => { this.userUID = user['uid']; this.searchesCollection = this.db.collection(`users/${this.userUID}/searches`); this.searchItems = this.searchesCollection.valueChanges().subscribe(data => { console.log(data); // works return data; }); }); console.log(this.searchItems); // undefined return this.searchItems; //undefined } } 我的问题是return语句,它返回undefined.它上面几行的console.log(data)返回我想要的值.我想知道为什么我会变得不确定.这可能是一个范围问题,但我似乎无法弄明白.它可能是一个我忽略的简单错误.有什么建议么? 谢谢!
您正在使用
async programming ,您无法暂停代码的执行,您的订阅将在未来解决,但您无法预测何时.订阅之外的console.log()在您的订阅被解决之前执行,这就是为什么它是未定义的,并且在订阅被解析之后调用subscribe回调中的console.log().为了更好地理解,请调用
this.
你可以做的是你可以将值存储在类属性中并在模板中访问它. getSearches() { this.afAuth.authState.subscribe(user => { this.userUID = user['uid']; this.searchesCollection = this.db.collection(`users/${this.userUID}/searches`); this.searchesCollection.valueChanges().subscribe(data => { console.log(data); // works this.searchItems=data; }); }); console.log(this.searchItems); // undefined return this.searchItems; //undefined } HTML {{searchItems?.//property}} 或者您可以使用异步管道 getSearches() { this.afAuth.authState.subscribe(user => { this.userUID = user['uid']; this.searchesCollection = this.db.collection(`users/${this.userUID}/searches`); this.searchItems=this.searchesCollection.valueChanges(); } HTML <ng-container *ngFor="let item of searchItems|async"> {{item?.//property}} <ng-container> LIVE DEMO (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |