webservice 服务器代码获取客户端的IP地址

通过 @Resource 注入 WebServiceContext 对象，再从 WebServiceContext 对象中使用 getMessageContext() 获得 MessageContext 对象，再使用：

ServletRequest request = (ServletRequest)messageContext.get(MessageContext.HTTP_REQUEST);

上面这些虽然是 Java EE 5/JAX-WS 2.0 中的方式，我看了一下 JAX-WS 2.1 中也可以使用的，你试试看。

所用的接口、Annotation 完整名称为：
@Resource: javax.annotation.Resource
WebServiceContext: javax.xml.ws.WebServiceContext
MessageContext: javax.xml.ws.handler.MessageContext
ServletRequest: javax.servlet.ServletRequest
?

@Resource
private WebServiceContext wsContext;

方法中
MessageContext mc = wsContext.getMessageContext();
HttpServletRequest request = (HttpServletRequest)(mc.get(mc.SERVLET_REQUEST));
String remortAddress = request.getRemoteAddr();
System.out.println(remortAddress);

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1.基于jax-ws开发的webservice获取客户端ip的方法【在代理类XXXDelegate添加如下代码】：

Java代码
1.import javax.annotation.Resource;??
2.import javax.servlet.http.HttpServletRequest;??
3.import javax.xml.ws.WebServiceContext;??
4.import javax.xml.ws.handler.MessageContext;??
5.?
6.@Resource?
7.private WebServiceContext wsContext;??
8.?
9.private String getClientInfo(){??
10.?
11.MessageContext mc = wsContext.getMessageContext();??
12.HttpServletRequest request = (HttpServletRequest)(mc.get(MessageContext.SERVLET_REQUEST));??
13.String remortAddress = request.getRemoteAddr();??
14.return (remortAddress);??
15.}?

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2.基于axis发布的webservice获取客户端ip的方法

Java代码

import org.apache.axis.MessageContext;
import org.apache.axis.transport.http.HTTPConstants;
import javax.servlet.http.HttpServletRequest;

1./**?
2.??? * 获取客户端IP地址，如调用方的IP，以便检查权限。?
3.??? * 适用于axis发布的webservice?
4.??? * @return?
5.??? */?
6.?? public String getClientIpAxis() {??
7.?????? MessageContext mc = null;??
8.?????? HttpServletRequest request = null;??
9.?????? try {??
10.?????????? mc = MessageContext.getCurrentMessageContext();??
11.?????????? if (mc == null)??
12.?????????????? throw new Exception(“无法获取到MessageContext”);??
13.?????????? request = (HttpServletRequest) mc??
14.?????????????????? .getProperty(HTTPConstants.MC_HTTP_SERVLETREQUEST);??
15.?????????? System.out.println(“remote? ip:? ” + request.getRemoteAddr());??
16.?????? } catch (Exception e) {??
17.?????????? System.out.println(e.getMessage());??
18.?????????? e.printStackTrace();??
19.?????? }??
20.?????? return request.getRemoteAddr();??
21.?? }?

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3.基于xfire发布的webservice获取客户端ip的方法

Java代码 1./**? 2.???? * 获取客户端IP地址? 3.???? * 适用于xfire发布的webservice? 4.???? * @return? 5.???? */? 6.??? public String getClientIpXfire() {?? 7.??????? String ip = “”;?? 8.??????? try {?? 9.??????????? HttpServletRequest request = XFireServletController.getRequest();?? 10.??????????? ip = request.getRemoteAddr();?? 11.??????? } catch (Exception e) {?? 12.??????????? System.out.println(“无法获取HttpServletRequest.”);?? 13.??????????? e.printStackTrace();?? 14.??????? }?? 15.??????? return ip;?? 16.??? }?