在bash中的测试语句中运行命令

用以下内容替换您显示的编码恐怖：

ls | head -1

并将其包含在您的测试语句中：

if [[ $(ls | head -1) = "arguprog.sh" ]]; then echo "TRUE"; else echo "FALSE"; fi

但这是错误的和破坏的(见下文).

现在更通用：不解析ls的输出.如果要在当前目录中找到第一个文件(或目录或…),请使用globs和此方法：

shopt -s nullglob
files=( * )
# The array files contains the names of all the files (and directories...)
# in the current directory,sorted by name.
# The first one is given by the expansion of "${files[0]}". So:
if [[ "${files[0]}" = "arguprog.sh" ]]; then echo "TRUE"; else echo "FALSE"; fi

请注意,解析ls的方法是错误的.看：

$# Create a new scratch dir
$mkdir myscratchdir
$# Go in there
$cd myscratchdir
$# touch a few files:
$touch $'arguprog.shnwith a newline' "some other file"
$# I created 2 files,none of them is exactly arguprog.sh. Now look:
$if [[ $(ls | head -1) = "arguprog.sh" ]]; then echo "TRUE"; else echo "FALSE"; fi
TRUE
$# HORROR!

对此有扭曲的解决方法,但实际上,最好的方法就是我刚给你的方法.

完成！