scala – 使用Akka Actors的OutOfMemoryError
发布时间:2020-12-16 18:36:31  所属栏目:安全  来源:网络整理 
            导读:我有一个使用RabbitMQ消息的应用程序,我正在使用Actors来处理工作. 这是我的方法: object QueueConsumer extends Queue { def consumeMessages = { setupListener(buildChannel(resultsQueueName),resultsQueueName,resultsCallback) } private def setupLi
                
                
                
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 我有一个使用RabbitMQ消息的应用程序,我正在使用Actors来处理工作. 
  
  这是我的方法: object QueueConsumer extends Queue {
  def consumeMessages = {
    setupListener(buildChannel(resultsQueueName),resultsQueueName,resultsCallback)
  }
  private def setupListener(receivingChannel: Channel,queue: String,f: (String) => Any) {
    Akka.system.scheduler.scheduleOnce(Duration(10,TimeUnit.SECONDS),Akka.system.actorOf(Props(new QueueActor(receivingChannel,queue,f))),"")
  }
}
class QueueActor(channel:Channel,queue:String,f:(String) => Any) extends Actor{
  def receive = {
    case _ => startReceiving
  }
  def startReceiving = {
    val consumer = new QueueingConsumer(channel)
    channel.basicConsume(queue,false,consumer)
    while (true) {
      val delivery = consumer.nextDelivery()
      val msg = new String(delivery.getBody())
      context.actorOf(Props(new Actor {
    def receive = {
      case some: String => f(some)
    }
      })) ! msg
      channel.basicAck(delivery.getEnvelope.getDeliveryTag,false)
    }
  }
}运行几秒钟后,它会抛出java.lang.OutOfMemoryError:超出GC开销限制. 我认为它正在发生,因为我正在为我收到的每条消息开始一个新的Actor – 所以如果我有100000条消息,它将创建10万个演员.这是一个好方法还是我应该实现像’演员池’这样的东西? 任何人都知道如何在我的场景中避免OutOfMemoryError? 预先感谢. EDIT1: 改变方法: class Queue2(json:String) extends Actor {
  def receive = {
    case x: String =>
      val envelope = MessageEnvelopeParser.toObject(x)
      val processor = ProcessQueueServiceFactory.getProcessResultsService()
      envelope.messages.foreach(message => processor.process(message))
  }
}
object Queue2 {
  def props(json: String): Props = Props(new Queue2(json))
}
class QueueActor(channel:Channel,queue:String) extends Actor {
  def receive = {
    case _ => startReceiving
  }
  def startReceiving = {
    val consumer = new QueueingConsumer(channel)
    channel.basicConsume(queue,consumer)
    while (true) {
      val delivery = consumer.nextDelivery()
      val msg = new String(delivery.getBody())
      context.actorOf(Queue2.props(msg))
      channel.basicAck(delivery.getEnvelope.getDeliveryTag,false)
    }
  }
}解决方法
 你的每个消息的演员在完成后需要自己停止,否则他们会永远呆在那里.请参阅 
 Actor lifecycle和 
 stopping Actors上的文档.在这里,您只需要在处理完成后添加context.stop(self).
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