[WebService]WebService初级教程（一）

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接口：

package cicro;

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public interface Isayhello

{
????? ?public String example(String message);
}

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实现类：

package cicro;

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public class sayhelloImpl implements Isayhello

{
?? public String example(String message)

?{
??? return message;
? }
}

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web.xml文件的配置：

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<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns="http://java.sun.com/xml/ns/j2ee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" version="2.4" xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee?? http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">
? <servlet>
??? <servlet-name>XFireServlet</servlet-name>
??? <servlet-class>org.codehaus.xfire.transport.http.XFireConfigurableServlet</servlet-class>
??? <load-on-startup>0</load-on-startup>
? </servlet>
? <servlet-mapping>
??? <servlet-name>XFireServlet</servlet-name>
??? <url-pattern>/services/*</url-pattern>
? </servlet-mapping>
? <welcome-file-list>
??? <welcome-file>index.jsp</welcome-file>
? </welcome-file-list>
</web-app>

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services.xml文件的配置；

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<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://xfire.codehaus.org/config/1.0">

?<service>
??<name>sayhello</name>
??<serviceClass>cicro.Isayhello</serviceClass>
??<implementationClass>cicro.sayhelloImpl</implementationClass>
??<style>wrapped</style>
??<use>literal</use>
??<scope>application</scope>
?</service></beans>

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整个工程目录如下：

在tomcat/webapp目录下创建一个名为webservice的目录；目录结构如下：

?????? webservice

????????????? |

????????????? |------WEB-INF

???????????????????? |

???????????????????? |-----classes

???????????????????? |????? |

???????????????????? |????? |----META-INF

???????????????????? |???????????? ??? |

???????????????????? |???????????? ??? |-----xfire

???????????????????? |?????????????????????????? |????????????

???????????????????? |?????????????????????????? |----services.xml????

???????????????????? |-----lib

|

???????????????????? ------web.xml

就要把此java文件编译后的class文件放在calsses目录下

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把xfire所需要的jar放在lib目录下

启动tomcat 在浏览器地址栏中输入：

http://localhost:8080/webservice/services/

如果能够显示 xml文档那么我们的一个webservice服务就算发布成功了；