在Scala中将(任一个的未来列表)转换为(列表中的任一个的未来)

以下示例显示了我的问题.

import scala.concurrent.Future
import scala.concurrent.ExecutionContext.Implicits.global

case class MyBoard(id: Option[Int],name: String)
case class MyList(id: Option[Int],name: String,boardId: Option[Int] = None)
case class ErrorCreatingList(error: String)

def createList(myList: MyList): Future[Either[ErrorCreatingList,MyList]] =
  Future {
    // Let's close our eyes and pretend I'm calling a service to create this list
    Right(myList)
  }

def createLists(myLists: List[MyList],myBoard: MyBoard): Future[Either[ErrorCreatingList,List[MyList]]] = {

  val listsWithId: List[Future[scala.Either[ErrorCreatingList,MyList]]] =
    myLists.map { myList =>
      createList(myList.copy(boardId = myBoard.id))
    }

  //  Meh,return type doesn't match
  ???
}

我希望createLists返回Future [[ErrorCreatingList,List [MyList]]]但我不知道怎么做,因为listsWithId的类型为List [Future [scala.Either [ErrorCreatingList,MyList]]],这使得感.

有办法吗？一位朋友告诉我“这就是Cats的用途”,但这是唯一的选择,我的意思是,我不能只使用Scala核心库中的内容吗？

谢谢.