减少Scala中的循环?
发布时间:2020-12-16 09:03:42 所属栏目:安全 来源:网络整理
导读:第一天和第一次尝试使用 Scala – 所以对我来说很容易!我正在尝试重写一些旧的 Java代码,它只是一个函数,它接受两个数字并打印出从x到y的数字.例如,我有增量功能: def increment(start: Int,finish: Int) = { for (i - start to finish) { println("Curren
第一天和第一次尝试使用
Scala – 所以对我来说很容易!我正在尝试重写一些旧的
Java代码,它只是一个函数,它接受两个数字并打印出从x到y的数字.例如,我有增量功能:
def increment(start: Int,finish: Int) = { for (i <- start to finish) { println("Current value (increasing from "+start+" to "+finish+") is "+i) } } 然而,我正在努力写一个相应的减量函数,从开始到结束将减少?我读过Scala downwards or decreasing for loop?但仍然不确定 谢谢 解决方法scala>def decrement(start: Int,finish: Int) = { | for (i <- start to finish by -1) | println("Current value (decreasing from "+start+" to "+finish+") is "+i); | } decrement: (start: Int,finish: Int)Unit scala> decrement(10,1) Current value (decreasing from 10 to 1) is 10 Current value (decreasing from 10 to 1) is 9 Current value (decreasing from 10 to 1) is 8 Current value (decreasing from 10 to 1) is 7 Current value (decreasing from 10 to 1) is 6 Current value (decreasing from 10 to 1) is 5 Current value (decreasing from 10 to 1) is 4 Current value (decreasing from 10 to 1) is 3 Current value (decreasing from 10 to 1) is 2 Current value (decreasing from 10 to 1) is 1 (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |