bash – 一个简单的小shell脚本来计算平均值

发布时间：2020-12-15 22:31:38 所属栏目：安全来源：网络整理

导读：谁能告诉我这里我做错了什么？ #!/bin/shif [ $# = 0 ]then echo "Usage: $0 filename" exit 1fisum=0count=0while [ $0 != 0 ]do sum="$sum"+"$2" count="$count"+ 1doneif [ "$count" != 0 ]then avg="$sum"/"$count" printf "Sum= $sum n Count= $count

谁能告诉我这里我做错了什么？

#!/bin/sh

if [ $# = 0 ]
then
    echo "Usage: $0 <filename>"
    exit 1
fi

sum=0
count=0

while [ $0 != 0 ]
do
        sum="$sum"+"$2"
        count="$count"+ 1

done
if [ "$count" != 0 ]
then
        avg="$sum"/"$count"
        printf "Sum= $sum n Count= $count  n Avg= $avg"
        exit 0
else
        printf "Sum= $sum n Count= $count  n Avg= undefined"
        exit 0
fi
exit 1

这是我尝试测试代码时的输出：

./average

sum: =: No such file or directory
sum: 0: No such file or directory
./average: 11: count: not found
[: 18: !=0: unexpected operator
./average: 25: Syntax error: Unterminated quoted string

基本上,如果我有一个看起来像这样的文件：

FirstPerson 23 

SecondPerson 36

ThirdPerson 22

我希望能够将其读入我的程序并输出：

Sum = FirstPerson+SecondPerson+ThirdPerson

Count = NumberofPeople

Average = Sum/Count

解决方法

下面的代码有效,你可以根据需要优化它(或使用awk,perl等)：

#!/bin/bash

if [ $# -ne 1 ]; then
        echo "Usage: "$0" <filename>"
        exit
fi

if [ ! -f $1 ]; then
        echo "$1 file not found."
        echo "Usage: $0 <filename>"
        exit
fi

sum=0
count=0
arq=$1

while read line
do
        num=`echo ${line#* }`
        sum=`expr $sum + $num`
        count=`expr $count + 1`
done < "$arq"

if [ "$count" != 0 ]
then
        avg=`expr $sum / $count`
        printf "Sum= "$sum" n Count= "$count"  n Avg= "$avg""
        exit 0
else
        printf "Sum= "$sum" n Count= "$count"  n Avg= undefined"
        exit 0
fi

（编辑：李大同）

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