企业级通过shell脚本开发MySQL启动脚本 案例
发布时间：2020-12-15 16:45:17 所属栏目：安全 来源：网络整理
导读：企业Shell面试题10：开发MySQL启动脚本 说明 MySQL启动命令为： /bin/shmysqld_safe--pid-file=$mysqld_pid_file_path21/dev/null 停止命令为： mysqld_pid=`cat"$mysqld_pid_file_path"` if(kill-0$mysqld_pid2/dev/null) then kill$mysqld_pid sleep2 fi
|
企业Shell面试题10：开发MySQL启动脚本 [root@db02scripts]#cat/etc/init.d/oldgirl
#Time:2017-07-0709:24:34 #Name:
#Version:V1.0 #Description:Thisisatestscript. [-f/etc/init.d/functions]&&source/etc/init.d/functions Port=3306 User="root" Bindir="/application/mysql/bin" Datadir="/application/mysql/data" mysqld_pid_file_path="/application/mysql/`hostname`.pid" PATH="/sbin:/usr/sbin:/bin:/usr/bin:$basedir/bin" exportPATH return_value=0 #Lockdirectory. lockdir='/var/lock/subsys' lock_file_path="$lockdir/mysql" log_success_msg(){ echo"SUCCESS!$@" } log_failure_msg(){ echo"ERROR!$@" } case"$1"in start) #Startdaemon echo"StartingMySQL" iftest-x$Bindir/mysqld_safe then $Bindir/mysqld_safe--datadir="$Datadir"--pid-file="$mysqld_pid_file_path">/dev/null& return_value=$? sleep2 #MakelockforCentOS iftest-w"$lockdir" then touch"$lock_file_path" fi exit$return_value else log_failure_msg"Couldn'tfindMySQLserver($bindir/mysqld_safe)" fi ;; stop) iftest-s"$mysqld_pid_file_path" then mysqld_pid=`cat"$mysqld_pid_file_path"` if(kill-0$mysqld_pid2>/dev/null) then echo"ShuttingdownMySQL" kill$mysqld_pid return_value=$? sleep2 else log_failure_msg"MySQLserverprocess#$mysqld_pidisnotrunning!" rm-f"$mysqld_pid_file_path" fi #DeletelockforCentOS iftest-f"$lock_file_path" then rm-f"$lock_file_path" fi exit$return_value else log_failure_msg"MySQLserverPIDfilecouldnotbefound!" fi ;; restart) if$0stop;then $0start else log_failure_msg"Failedtostoprunningserver,sorefusingtotrytostart." exit1 fi ;; *) echo"Usage:$0{start|stop|restart}" exit1 ;; esac exit$return_value 函数版： #!/bin/bash
#Time:2017-07-0709:24:34 #Name:
（编辑：李大同） 【声明】本站内容均来自网络，其相关言论仅代表作者个人观点，不代表本站立场。若无意侵犯到您的权利，请及时与联系站长删除相关内容! |
推荐文章
站长推荐
热点阅读