linux – 为脚本日志条目添加时间戳

目前,我使用exec 22>& 2 21>& 1 1> $log 2>& 1将我的bash脚本写入stderr和stdout到日志文件.我想为每个条目添加一个时间戳,但我还没有找到一个简单的方法来做到这一点.理想情况下,对当前命令进行简单的更改,然后在其余部分之前将时间写在同一行上.

这是我正在使用命令的脚本：

#!/bin/bash

#This script takes the server to rysnc as an argument. You can also tell 
#the script to check the server_status.txt file.
#
#Example: /path/to/script/sync.sh grail true
#
#The arguments are order senstive. The server name must come before the status
#check value.

#Logfile
LOG=/var/log/sync.log

DIRECTORYS="auth/ keys/ log/mailwhen/ intranet/ www/calmaa/data/ www/admatch/data/ www/sfhsa/data/ www/hfa3_org www/padmatch/ www/serverdown/"

if [ "x$2" == "xfalse" ]; then
    return 0
elif [ "x$2" == "xtrue" ]; then
    if [ `cat /srv/www/wan*/server_status.txt` == "primary" ]; then
        exit 0
    fi
else
    echo "Please use "true" or "false" for the second value." 
    exit 1
fi

# Copy stdout and stderr,and then open the logfile
exec 22>&2 21>&1 1>$log 2>&1
# Here is how to restore stdout and stderr:
# exec 2>&22 1>&21

for DIRECTORY in $DIRECTORYS; do
    rsync -azu --delete --bwlimit=500 $1:/srv/$DIRECTORY  /srv/$DIRECTORY
done

exec > >(while read -r line; do printf '%s %sn' "$(date --rfc-3339=seconds)" "$line"; done)

2013-09-04 21:32:14-05:00 An event occurred and this is the message
2013-09-04 21:32:37-05:00 Some time passed,another event produced a message