Linux Script嵌套if语句给出语法错误
发布时间:2020-12-14 00:51:50 所属栏目:Linux 来源:网络整理
导读:我试图嵌套多个if语句如下: #!/bin/bash# start_server.sh# # Use this script to start the MarketDataTransmitter.## Usage: ./start_server.sh Starts the MarketDataTransmitter.reset=$(tput sgr0)red=$(tput setaf 1)green=$(tput setaf 2)yellow=$(t
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我试图嵌套多个if语句如下:
#!/bin/bash
# start_server.sh
#
# Use this script to start the MarketDataTransmitter.
#
# Usage: ./start_server.sh Starts the MarketDataTransmitter.
reset=$(tput sgr0)
red=$(tput setaf 1)
green=$(tput setaf 2)
yellow=$(tput setaf 3)
cyan=$(tput setaf 6)
echo
directory=$(ls -l)
check_exist=$(awk -v a="$directory" -v b="MarketDataTransmitter" 'BEGIN { print index(a,b) }')
if [ "$check_exist" = "0" ]; then
# MarketDataTransmitter is not present.
echo "${red}[ERROR]${reset} Could not start ${yellow}MarketDataTransmitter${reset}."
echo " ${yellow}MarketDataTransmitter${reset} could not be found."
else
# MarketDataTransmitter is present.
processes=$(ps -ef | grep -i "MarketDataTransmitter" | grep -v "grep" | grep -v "bash" | awk '{ print $8 }')
check_run=$(awk -v a="$processes" -v b="MarketDataTransmitter" 'BEGIN { print index(a,b) }')
if [ "$check_run" = "0" ]; then
# MarketDataTransmitter is not running.
if [ -e "srv.log" ]; then
if [ -s "srv.log" ]; then
if [ -d "logs" ]; then
date_time=$(date '+%Y%m%d_%H_%M_%S')
new_log_name="srv_$date_time.log"
mv srv.log $new_log_name
mv $new_log_name logs
else
mkdir logs
date_time=$(date '+%Y%m%d_%H_%M_%S')
new_log_name="srv_$date_time.log"
mv srv.log $new_log_name
mv $new_log_name logs
fi
else
echo "srv.log is empty and will be removed."
rm -rf srv.log
fi
else
# No srv.log but this is to start MarketDataTransmitter so we can ignore.
fi
./MarketDataTransmitter > srv.log &
echo "${yellow}MarketDataTransmitter${reset} has been started."
else
# MarketDataTransmitter is already running.
echo "${red}[ERROR]${reset} Could not start ${yellow}MarketDataTransmitter${reset}."
echo " ${yellow}MarketDataTransmitter${reset} is already running."
fi
fi
echo
然而它给我语法投诉说: 意外标记’fi’附近的语法错误 在最后一个’fi’ 有谁知道为什么? 谢谢. [编辑]已发布完整代码. 解决方法
你有一个else语句和fi语句,在44-46行之间没有任何内容(只是它们之间的注释).在bash中,你需要在else块的主体中??有一些语句,或者取出else块.
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