生成随机颜色的问题 – asp.net和c#

如果担心要避免连续绘制两个“相似”颜色,则应采取以下响应.连续避免两种相似的颜色意味着

>使用一些数学逻辑(但是存在使用的函数不能覆盖所有可能颜色的光谱的风险,因为一个像样的随机数生成器会)
>绘制真正的随机颜色,但当它们被视为相似时拒绝它们(并重新尝试).

第二种方法是以下代码段中说明的内容.
风格是手写的,颜色验收标准有点武断,但这应该提供一个好主意.
此外,通过重复使用单个随机数发生器(RNG),可以避免重复序列的风险,如果每次都以某种方式创建RNG,并且偶然使用相同的种子……

const int minTotalDiff = 200;    // parameter used in new color acceptance criteria
  const int okSingleDiff = 100;    // id.

  int prevR,prevG,prevB;  // R,G and B components of the previously issued color.
  Random RandGen = null;

  public string GetNewColor()
  {
      int newR,newG,newB;

      if (RandGen == null)
      {
          RandGen = new Random();
          prevR = prevG = prevB = 0;
      }

      bool found = false;
      while (!found)
      {
          newR = RandGen.Next(255);
          newG = RandGen.Next(255);
          newB = RandGen.Next(255);

          int diffR = Math.Abs(prevR - newR);
          int diffG = Math.Abs(prevG - newG);
          int diffB = Math.Abs(prevB - newB);

          // we only take the new color if...
          //   Collectively the color components are changed by a certain
          //   minimum
          //   or if at least one individual colors is changed by "a lot".
          if (diffR + diffG + diffB >= minTotalDiff
              || diffR >= okSingleDiff
              || diffR >= okSingleDiff
              || diffR >= okSingleDiff
          )
            found = true;
        }

       prevR = newR;
       prevG = newG;
       prevB = newB;

      return String.Format("#{0:X2}{0:X2}{0:X2}",prevR,prevB);
  }