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python – 如何将args传递给信号

发布时间:2020-12-20 13:29:09 所属栏目:Python 来源:网络整理
导读:views.py: user = User.objects.create_user(username=username,email=email) user.password=password1#user.set_password(password1)user.save() models.py: def create_user_profile(sender,instance,created,**kwargs): if created: #here i want user
views.py:

user = User.objects.create_user(username=username,email=email)          
user.password=password1
#user.set_password(password1)
user.save()

models.py:

def create_user_profile(sender,instance,created,**kwargs):
    if created:
        #here i want user password unencrypted where I pass that parameter to this
      signal

        post_save.connect(create_user_profile,sender=User)

解决方法

Sending signals

There are two ways to send send signals in Django.

Signal.send(sender,**kwargs)

Signal.send_robust(sender,**kwargs)

https://docs.djangoproject.com/en/dev/topics/signals/#sending-signals

在你的情况下,你可能会做这样的事情

# not the real word code.
Signal.send(User,raw_password="xxx")

# raw password stays in **kwargs

def create_user_profile(sender,**kwargs):

if created:
      //here i want user password unencrypted where I pass that parameter to this
      raw_pass = kwargs.get('raw_password')

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