在python中返回1而不是true

我正在处理的代码是：

delimiters = ( '()','[]','{}',"''",'""' )
esc = ''

def is_balanced(s,delimiters=delimiters,esc=esc):
    stack = []
    opening = tuple(str[0] for str in delimiters)
    closing = tuple(str[1] for str in delimiters)
    for i,c in enumerate(s):
        if len(stack) and stack[-1] == -1:
            stack.pop()
        elif c in esc:
            stack.append(-1)
        elif c in opening and (not len(stack) or opening[stack[-1]] != closing[stack[-1]]):
            stack.append(opening.index(c))
        elif c in closing:
            if len(stack) == 0 or closing.index(c) != stack[-1]:
                return False
            stack.pop()

    return len(stack) == 0

num_cases = raw_input()
num_cases = int(num_cases)
for num in range(num_cases):
    s = raw_input()
    print is_balanced(s)

它基本上检查键入的字符串是否平衡.如果平衡,应返回1,如果不是0.

我试过这个：

1
Test string
True

它返回true.我希望它返回1.我该怎么办？