python 递归\for循环_斐波那契数列
发布时间:2020-12-20 12:48:11 所属栏目:Python 来源:网络整理
导读:# 递归 def myAdd(a,b): c = a + b print (c) if c 100 : return return myAdd(a + 1,c) # 最大递归深度是1000 myAdd(2,3 ) # 功能同上递归 a = 2 b = 3 for i in range(1000 ): c = a + b print (c) a += 1 b = c def myFibo(a,b): c = a + b print (c) if
# 递归 def myAdd(a,b): c = a + b print(c) if c > 100: return return myAdd(a + 1,c) #最大递归深度是1000 myAdd(2,3) # 功能同上递归 a = 2 b = 3 for i in range(1000): c = a + b print(c) a += 1 b = c def myFibo(a,b): c = a + b print(c) if c > 500: return return myFibo(b,c) myFibo(0,1) a = 0 b = 1 for i in range(1000): c = a + b print(c) a = b b = c if c > 500: break (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |