Python初学者.这个Python代码是否尽可能高效？

发布时间：2020-12-20 12:17:45 所属栏目：Python 来源：网络整理

导读：这个问题/解决方案让我想到另一个相关的问题 here – 帮助将不胜感激！根据初步反馈更新了以下当前代码我是Python的新手(这是我的第二个程序).我目前正在使用麻省理工学院的开放课件使用Python Academic Earth videos来介绍CS,我正在研究问题集1 Viewable

这个问题/解决方案让我想到另一个相关的问题 here – 帮助将不胜感激！

根据初步反馈更新了以下当前代码

我是Python的新手(这是我的第二个程序).我目前正在使用麻省理工学院的开放课件使用Python Academic Earth videos来介绍CS,我正在研究问题集1 Viewable Here.我创建了这个程序,在12个月内成功重建了“测试用例1”(不包括“结果”) “部分……仍在努力”但我的问题是,以下(我的)代码是否尽可能高效？当我没有必要时,我觉得我正在重复自己. ：

原始代码：

balance = float(raw_input("Outstanding Balance: "))
interestRate = float(raw_input("Interest Rate: "))
minPayRate = float(raw_input("Minimum Monthly Payment Rate: "))
interestPaid = round((interestRate/12.0)*balance,2)
minPayment = round(minPayRate*balance,2)
principalPaid = round(minPayment-interestPaid,2)
remainingBalance = round(balance-principalPaid,2)
month = 1

while month < 12 :    
    if month > 1 :
        balance = remainingBalance
    interestPaid = round((interestRate/12.0)*balance,2)
    minPayment = round(minPayRate*balance,2)
    principalPaid = round(minPayment-interestPaid,2)
    remainingBalance = round(balance-principalPaid,2)   
    month = month+1

    print 'Month: ' + str(month)
    print 'Minimum monthly payment: ' + str(minPayment)
    print 'Principle paid: ' + str(principalPaid)
    print 'Remaining balance: ' + str(remainingBalance)

现行守则

balance = float(raw_input("Outstanding Balance: "))
interestRate = float(raw_input("Interest Rate: "))
minPayRate = float(raw_input("Minimum Monthly Payment Rate: "))

for month in xrange(1,12+1):
    interestPaid = round(interestRate / 12.0 * balance,2)
    minPayment = round(minPayRate * balance,2)
    principalPaid = round(minPayment - interestPaid,2)
    remainingBalance = round(balance - principalPaid,2)

    print 'Month: %d' % (month,)
    print 'Minimum monthly payment: %.2f' % (minPayment,)
    print 'Principle paid: %.2f' % (principalPaid,)
    print 'Remaining balance: %.2f' % (remainingBalance,)

    balance = remainingBalance

如果您在此新代码中看到任何其他内容,请告诉我们！

非常感谢那些帮助我实现这一目标的人.

解决方法

print "x: " + str(x)

应该替换为：

print "x:",x

这是打印的特例.

将循环更改为：

for month in xrange(1,12+1):

删除第一个循环的检查,然后将余额设置为remainingBalance作为结束.

因为您手动增加月份,所以每次都打印错误的值.

如果你的效率和执行效率一样,那你就担心too soon了.如果你的意思是复制代码,你会在循环之前不必要地复制数学.结合以上内容：

balance = float(raw_input("Outstanding Balance: "))
interestRate = float(raw_input("Interest Rate: "))
minPayRate = float(raw_input("Minimum Monthly Payment Rate: "))

for month in xrange(1,12+1):    
  interestPaid = round(interestRate / 12.0 * balance,2)
  minPayment = round(minPayRate * balance,2)
  principalPaid = round(minPayment - interestPaid,2)
  remainingBalance = round(balance - principalPaid,2)   

  print 'Month:',month
  print 'Minimum monthly payment:',minPayment
  print 'Principle paid:',principalPaid
  print 'Remaining balance:',remainingBalance

  balance = remainingBalance

（编辑：李大同）

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