python – 使用索引列表从字典中获取值
发布时间:2020-12-20 12:14:31 所属栏目:Python 来源:网络整理
导读:给出一个清单: x = [0.0,0.87,0.0,0.32,0.46,0.10,0.0] 我想得到所有非0值的索引,并将它们存储在d [‘inds’]中 然后使用d [‘inds’]中的索引遍历x列表并获取值. 所以我会得到类似的东西: d['inds'] = [1,5,6,9]d['vals'] = [0.87,0.10] 我已经使用了索引
给出一个清单:
x = [0.0,0.87,0.0,0.32,0.46,0.10,0.0] 我想得到所有非0值的索引,并将它们存储在d [‘inds’]中 d['inds'] = [1,5,6,9] d['vals'] = [0.87,0.10] 我已经使用了索引: d['inds'] = [i for i,m in enumerate(x) if m != 0] 但我不知道如何得到d [‘vals’] 解决方法d['vals'] = [x[i] for i in d['inds']] 更好的是,同时做两件事: vals = [] inds = [] for i,v in enumerate(x): if v!=0: vals.append(v) inds.append(i) d['vals']=vals d['inds']=inds 要么 import numpy as np d['inds'],d['vals'] = np.array([(i,v) for i,v in enumerate(x) if v!=0]).T (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |