如何将python提供的时间转换为int

发布时间：2020-12-20 11:39:32 所属栏目：Python 来源：网络整理

导读：这是我的以下代码： from time import sleepimport datetimeprint ("This is a game where you guess when 10 seconds have passed")sleep (0.5)input("Hit the enter key when you are ready")start = datetime.datetime.now().time()sleep (1)print ("1")s

这是我的以下代码：

from time import sleep
import datetime
print ("This is a game where you guess when 10 seconds have passed")
sleep (0.5)
input("Hit the enter key when you are ready")
start = datetime.datetime.now().time()
sleep (1)
print ("1")
sleep (1)
print ("2")
sleep (1)
print ("3...")
input
end = datetime.datetime.now().time()
time = (end) - (start)

当它到达第17行时出现错误(直到它计数到3之后)这是错误：

Traceback (most recent call last):
  File "D:/Python/Scripts/Challenges/Challenge 6 - Time Guessing Game.py",line 17,in <module>
    time = (end) - (start)
TypeError: unsupported operand type(s) for -: 'datetime.time' and 'datetime.time'

我说我在python上很可怕,但我需要知道的是我如何将时间变成一个整数,这样我就可以减去它并得到它们第二次按Enter键的时间.
谢谢你：D
我很抱歉啊哈

解决方法

你可以只使用时间,你不需要日期时间来减去秒数：

from time import sleep,time

print ("This is a game where you guess when 10 seconds have passed")
sleep (0.5)
input("Hit the enter key when you are ready")
start = time()
sleep (1)
print ("1")
sleep (1)
print ("2")
sleep (1)
print ("3...")
input()
end = time()
diff = end - start
print(diff)

如果你想把秒作为int使用print(int(diff))

（编辑：李大同）

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