python – 按组件排序字符串列表
发布时间：2020-12-20 11:38:57 所属栏目：Python 来源：网络整理
导读：长列表包含一些要排序的元素. 实际上每个元素有4个内容：名称,输入/输出,区域和日期时间,由’?’连接. (‘?’可以更改.)我想将列表重组为排序顺序. a_list = ["Chris~Check-in~Zoom A~11/13/2013 05:20","Chris~Check-in~Zoom G~11/15/2013 14:09","Frank E~
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长列表包含一些要排序的元素.
实际上每个元素有4个内容：名称,输入/输出,区域和日期&时间,由’?’连接. (‘?’可以更改.)我想将列表重组为排序顺序. a_list = ["Chris~Check-in~Zoom A~11/13/2013 05:20","Chris~Check-in~Zoom G~11/15/2013 14:09","Frank E~Check-in~Zoom K~11/11/2013 08:48","Frank E~Check-in~Zoom K~11/15/2013 21:32","Kala Lu S~Check-in~Zoom N~11/13/2013 07:20","Milly Emily~Check-in~Zoom G~11/13/2013 01:08","Milly Emily~Check-in~Zoom E~11/16/2013 14:39","Milly Amy~Check-in~Zoom G~11/10/2013 20:14","Milly Amy~Check-in~Zoom A~11/16/2013 08:55","Milly Amy~Check-in~Zoom O~11/14/2013 21:57","Milly Amy~Check-in~Zoom A~11/15/2013 10:45","Nago Iko~Check-in~Zoom K~11/16/2013 20:42","Nago Iko~Check-in~Zoom K~11/14/2013 10:46","Liz D~Check-in~Zoom N~11/15/2013 01:46","Liz D~Check-in~Zoom A~11/12/2013 09:54","Liz D~Check-in~Zoom G~11/16/2013 13:15","Chris~Check-out~Zoom A~11/13/2013 13:42","Chris~Check-out~Zoom G~11/11/2013 14:21","Chris~Check-out~Zoom G~11/16/2013 09:41","Frank E~Check-out~Zoom K~11/14/2013 03:02","House P~Check-out~Zoom K~11/10/2013 11:17","Kala Lu S~Check-out~Zoom G~11/11/2013 23:27","Kala Lu S~Check-out~Zoom N~11/14/2013 11:17"] 它可以导入到MS Excel并进行排序,但我想知道Python是否可以完成这项工作. 是否可以按列表中的顺序对它们进行排序：1.名称,2.日期和时间3.区域4.进/出？喜欢： new_list = ["Chris~Check-out~Zoom G~11/08/2014 14:21","Chris~Check-in~Zoom A~11/10/2014 05:20","Chris~Check-out~Zoom A~11/10/2014 13:42","Chris~Check-in~Zoom G~11/12/2014 14:09","Chris~Check-out~Zoom G~11/13/2014 09:41","Frank E~Check-in~Zoom K~11/08/2014 08:48","Frank E~Check-out~Zoom K~11/11/2014 03:02","Frank E~Check-in~Zoom K~11/12/2014 21:32",... ...] 谢谢. 解决方法
您可以拆分列表,然后使用自定义键功能进行排序.但是您需要首先解析日期以正确排序它们.
import datetime
new_l = sorted((x.split('~') for x in l),key=lambda x: (x[0],datetime.datetime.strptime(x[3],'%m/%d/%Y %H:%M'),x[2],x[1]))
键函数返回一个元组.元组按字典顺序进行比较;比较第一项;如果它们相同则比较第二项,依此类推 或者,您可以分阶段进行分类.这将允许您指定要按升序或降序排序的列. from operator import itemgetter
nl = [x.split('~') for x in l]
nl.sort(key=itemgetter(1))
nl.sort(key=itemgetter(2))
nl.sort(key=lambda x: datetime.datetime.strptime(x[3],reverse=True) # Newest first
nl.sort(key=itemgetter(0))
请记住,两种方式都会使新列表分割如下： new_list = [["Chris","Check-out","Zoom G","11/08/2014 14:21"],...] 如果要将它们更改回原始表单,可以加入它们： new_list_joined = ['~'.join(x) for x in new_list] （编辑：李大同） 【声明】本站内容均来自网络，其相关言论仅代表作者个人观点，不代表本站立场。若无意侵犯到您的权利，请及时与联系站长删除相关内容! |