python-2.7 – .ix上的按位运算(Pandas)

>>> df = pd.DataFrame({"a": [-1,2,-3,4,6,-8.2]})
>>> df.ix[(df['a'] <= 0) | (df['a'] > 5)]
     a
0 -1.0
2 -3.0
4  6.0
5 -8.2

否则,你试图执行按位操作(可能是)浮点数.例如,如果它是一个int,那么它“工作”：

>>> df['a'] <= 0 & df['a']
Traceback (most recent call last):
  File "<ipython-input-40-9173361ec31b>",line 1,in <module>
    df['a'] <= 0 & df['a']
TypeError: ufunc 'bitwise_and' not supported for the input types,and the inputs could not be safely coerced to any supported types according to the casting rule 'safe'

>>> df['a'] <= 0 & df['a'].astype(int)
0     True
1    False
2     True
3    False
4    False
5     True
Name: a,Dtype: bool