python和小时公式计算
发布时间:2020-12-20 11:22:02 所属栏目:Python 来源:网络整理
导读:我有一些工作代码,我改变了,但我似乎无法得到小时变量的数学.我想假期我需要很多食物,因为我想要一个空白. ## {{{ http://code.activestate.com/recipes/124894/ (r2)from Tkinter import *import timeimport pygtkimport gtkimport timeclass StopWatch(Fra
我有一些工作代码,我改变了,但我似乎无法得到小时变量的数学.我想假期我需要很多食物,因为我想要一个空白.
## {{{ http://code.activestate.com/recipes/124894/ (r2) from Tkinter import * import time import pygtk import gtk import time class StopWatch(Frame): """ Implements a stop watch frame widget. """ def __init__(self,parent=None,**kw): Frame.__init__(self,parent,kw) self._start = 0.0 self._elapsedtime = 0.0 self._running = 0 self.timestr = StringVar() self.makeWidgets() def makeWidgets(self): """ Make the time label. """ l = Label(self,textvariable=self.timestr) self._setTime(self._elapsedtime) l.pack(fill=X,expand=NO,pady=2,padx=2) def _update(self): """ Update the label with elapsed time. """ self._elapsedtime = time.time() - self._start self._setTime(self._elapsedtime) self._timer = self.after(50,self._update) def _setTime(self,elap): """ Set the time string to Minutes:Seconds:Hundreths """ hours = int(elap) #cant remember formula minutes = int(elap/60) seconds = int(elap - minutes*60.0) hseconds = int((elap - minutes*60.0 - seconds)*100) sn = time.strftime('%m/%d/%Y-%H:%M:%S') self.timestr.set('%02snn%02dh:%02dm:%02ds:%02d' % (sn,hours,minutes,seconds,hseconds)) def Start(self): """ Start the stopwatch,ignore if running. """ if not self._running: self._start = time.time() - self._elapsedtime self._update() self._running = 1 def Stop(self): """ Stop the stopwatch,ignore if stopped. """ if self._running: self.after_cancel(self._timer) self._elapsedtime = time.time() - self._start self._setTime(self._elapsedtime) self._running = 0 def Reset(self): """ Reset the stopwatch. """ self._start = time.time() self._elapsedtime = 0.0 self._setTime(self._elapsedtime) def main(): root = Tk() root.title( "Stop Watch" ) sw = StopWatch(root) sw.pack(side=TOP) Button(root,text='Start',command=sw.Start).pack(side=LEFT) Button(root,text='Stop',command=sw.Stop).pack(side=LEFT) Button(root,text='Reset',command=sw.Reset).pack(side=LEFT) Button(root,text='Quit',command=root.quit).pack(side=LEFT) root.mainloop() if __name__ == '__main__': main() ## end of http://code.activestate.com/recipes/124894/ }}} 解决方法
我从方程式推断出elap是以秒为单位测量的.由于您将小时数提取到单独的变量中,因此需要从分钟计数中删除它们.当然,由于分钟的含义与原始代码有所不同,因此您需要在计算的其余部分中遵循此操作.
hours = int(elap/3600) minutes = int((elap-hours*3600)/60) seconds = int(elap-hours*3600-minutes*60) hseconds = int((elap-hours*3600-minutes*60-seconds)*100) 我想如果我写这篇文章,我会修改elap,因为我一直在努力减少重复. hours = int(elap/3600) elap -= hours*3600 minutes = int(elap/60) elap -= minutes*60 seconds = int(elap) elap -= seconds hseconds = int(elap*100) 这样做可以更容易地看到正在发生的事情,并且将来也更容易修改.例如,如果您想在混合中添加天数,那么您需要做的就是将其移植到代码的开头: days = int(elap/86400) elap -= days*86400 现在,我在这里编写了代码,假设elap是一个浮点数,当然它在你的程序中.如果你特别偏执,你会在执行算术之前编写elap = float(elap). 但我同意@soulcheck认为使用库函数更清晰. (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |