python – SimpleJson处理相同的命名实体

发布时间：2020-12-20 11:21:24 所属栏目：Python 来源：网络整理

导读：我在app引擎中使用Alchemy API,所以我使用simplejson库来解析响应.问题是响应的条目具有sme名称 { "status": "OK","usage": "By accessing AlchemyAPI or using information generated by AlchemyAPI,you are agreeing to be bound by the AlchemyAPI Terms

我在app引擎中使用Alchemy API,所以我使用simplejson库来解析响应.问题是响应的条目具有sme名称

{
    "status": "OK","usage": "By accessing AlchemyAPI or using information generated by AlchemyAPI,you are agreeing to be bound by the AlchemyAPI Terms of Use: http://www.alchemyapi.com/company/terms.html","url": "","language": "english","entities": [
        {
            "type": "Person","relevance": "0.33","count": "1","text": "Michael Jordan","disambiguated": {
                "name": "Michael Jordan","subType": "Athlete","subType": "AwardWinner","subType": "BasketballPlayer","subType": "HallOfFameInductee","subType": "OlympicAthlete","subType": "SportsLeagueAwardWinner","subType": "FilmActor","subType": "TVActor","dbpedia": "http://dbpedia.org/resource/Michael_Jordan","freebase": "http://rdf.freebase.com/ns/guid.9202a8c04000641f8000000000029161","umbel": "http://umbel.org/umbel/ne/wikipedia/Michael_Jordan","opencyc": "http://sw.opencyc.org/concept/Mx4rvViVq5wpEbGdrcN5Y29ycA","yago": "http://mpii.de/yago/resource/Michael_Jordan"
            }
        }
    ]
}

所以问题是“子类型”被重复,因此负载返回的字典只是“TVActor”而不是列表.反正有没有绕过这个？

解决方法

定义application / json的 rfc 4627说：

An object is an unordered collection of zero or more name/value pairs

和：

The names within an object SHOULD be unique.

这意味着AlchemyAPI不应在同一对象内返回多个“subType”名称,并声称它是JSON.

您可以尝试以XML格式请求相同的内容(outputMode = xml)以避免结果中出现歧义或将重复键值转换为列表：

import simplejson as json
from collections import defaultdict

def multidict(ordered_pairs):
    """Convert duplicate keys values to lists."""
    # read all values into lists
    d = defaultdict(list)
    for k,v in ordered_pairs:
        d[k].append(v)

    # unpack lists that have only 1 item
    for k,v in d.items():
        if len(v) == 1:
            d[k] = v[0]
    return dict(d)

print json.JSONDecoder(object_pairs_hook=multidict).decode(text)

例

text = """{
  "type": "Person","subType": "AwardWinner"
}"""

产量

{u'subType': [u'Athlete',u'AwardWinner'],u'type': u'Person'}

（编辑：李大同）

【声明】本站内容均来自网络，其相关言论仅代表作者个人观点，不代表本站立场。若无意侵犯到您的权利，请及时与联系站长删除相关内容!