python两个字符串有变化值作对比
发布时间:2020-12-20 10:55:48 所属栏目:Python 来源:网络整理
导读:两个字符串作对比,实际值一些no变化,预期值中用*代替,以下是脚本 actual = ‘ {"Status": 1,"Content": {"order_no": "20190813173142658002396779806585","request_id": "4999870244479602310","status": "SUCCESS"},"Message": "请求成功"} ‘ expect =
两个字符串作对比,实际值一些no变化,预期值中用*代替,以下是脚本 actual = ‘{"Status": 1,"Content": {"order_no": "20190813173142658002396779806585","request_id": "4999870244479602310","status": "SUCCESS"},"Message": "请求成功"}‘ expect = ‘{"Status": 1,"Content": {"order_no": "*","request_id": "*","Message": "请求成功"}‘ count = 0 for expect_char in expect: count += 1 if expect_char == ‘*‘: # 遍历预期字符串,找到*位置 print(count) actual = actual[:count - 1] + "*" + actual[count:] # 把实际字符串该位置替换为* print(actual) for actual_char in actual[count:]: if actual_char == ‘"‘: # 依次替换后面的字符为空,直到引号,引号可以换为其他字符,亦可多个 break actual = actual[:count] + actual[count + 1:] print(actual,count) print(actual) 因为对性能要求不高,想提高性能,可替换字符串拼接方式。 (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |
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