python 列表推导式 题二

1 list1 = ["1.Just do it","2.一切皆有可能","3.让编程改变世界","Impossible is Nothing"]
2 list2 = ["4.阿迪达斯","2.李宁","3.python","1.耐克"]
3 list3 = [name + ":" + slogan[2:] for slogan in list1 for name in list2  if slogan[0]==name[0]]
4 
5 print(list3)
6 for each in list3:
7     print(each)

 1 list1 = ["1.Just do it","Impossible is Nothing"]
 2 list2 = ["4.阿迪达斯","1.耐克"]
 3 for slogan in list1:
 4                                 #遍历list1内容 获取口号slogan
 5     for name in list2:
 6                                 #遍历list2内容 获取品牌name
 7         if name[0] == slogan[0]:
 8                                 #如果name里下标0的字符与slogan里下标0的字符相同
 9             list3 = name + ":" + slogan[2:]
10                                 #进行加法和切片
11             print(list3)