Python 实现两个矩形重合面积

import math
x1,y1,x2,y2 = input().split(" ")
x1,y2=int(x1),int(y1),int(x2),int(y2)
# print(x1,y2)
x1,x2 = min(x1,x2),max(x1,x2)
y1,y2= min(y1,y2),max(y1,y2)

# print(x1,y2)

x3,y3,x4,y4 = input().split(" ")
x3,y4 = int(x3),int(y3),int(x4),int(y4)
x3,x4 = min(x3,x4),max(x3,x4)
y3,y4 = min(y3,y4),max(y3,y4)

# print(x3,y4)

if (x2<=x3 or x4<=x1) and (y2 <= y3 or y4<=y1):
    print(0)
else:
    lens = min(x2,x4) - max(x1,x3)
    wide = min(y2,y4) - max(y1,y3)
    print(lens*wide)

import string

in_str = input()
nums = string.digits

a = ""
strs = ""
num = ""
for i in range(len(in_str)):
    if in_str[i] not in nums:
        a = a+in_str[i]
    else:
        if i == len(in_str)-1 or (in_str[i+1] not in nums):
            num = int(num + in_str[i])
            strs = strs + a*num
            a=""
            num=""
        else:
            num = num + in_str[i]


print(strs)