Python元组与字符串操作（8）——三数排序多种实现

num1 = []
for i in range(3):
    num1.append(int(input(‘>>‘)))

num1b = None
if num1[0] > num1[1]:
    if num1[1] > num1[2]:
        num1b = [0,1,2]
    elif num1[0] > num1[2]:
        num1b = [0,2,1]
    else:
        num1b = [2,1]
else:
    if num1[0] > num1[2]:
        num1b = [1,2]
    elif num1[2] > num1[1]:
        num1b = [2,1,0]
    else:
        num1b = [1,2,0]

for i in num1b:
    print(num1[i])

nums = []
for i in range(3):
    nums.append(int(input(‘>>‘)))
#num1 = []
#while len(num1) < 3:
#    num1.append(int(input(‘>>‘)))

order = None
if nums[0] > nums[1]:
    if nums[1] > nums[2]:
        order = [2,0]
    else:
        if nums[0] > nums[2]:
            order = [1,0]
        else:
            order = [1,2]
else:
    if nums[2] > nums[1]:
        order = [0,2]
    else:
        if nums[0] > nums[2]:
            order = [2,1]
        else:
            order = [0,1]

for i in order:
    print(nums[i])

num2 = []
while len(num2) < 3:
    num2.append(int(input(‘>>‘)))

num2b = []
while len(num2) > 0:
    if len(num2) == 1:
        num2b.insert(0,num2[0])
        num2.clear()
    else:
        num2b.insert(0,max(num2))
        num2.remove(max(num2))

print(num2b)

nums = []
while len(nums) < 3:
    nums.append(int(input(‘>>‘)))

newlist = [None] * len(nums)
#for i in range(len(nums)):
index = -1
while nums:
    m = max(nums)
    newlist[index] = m
    nums.remove(m)
    if len(nums) == 1:
        newlist[0] = nums[-1]
        break
    index -= 1

print(newlist)

num3 = []
while len(num3) < 3:
    num3.append(int(input(‘>>‘)))

num3.sort()

print(num3)