【数据结构的补全整理】规定在周一到周五中，赛选出8点到18点中

# 数据表的设计

class ProMeetTable(models.Model):
    """
        个人安排表
    """
    user = models.ForeignKey(to="UserInfo",verbose_name=所属用户")
    week_choice = (
        (1,Monday),(2,1)">TuesdayWednesdayThursdayFriday星期)
    time_choice =08:0009:0010:0011:0012:0013:0014:0015:0016:0017:0018:00时刻)
    title = models.CharField(max_length=250,1)">安排True)

    def __str__(self):
        return self.title

     Meta:
        verbose_name = ProMeetTable
        verbose_name_plural = verbose_name
        db_table = ''



# 假设设计好的个人安排数据

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# 接口：


class ProData(APIView):

    authentication_classes = []

    def post(self,request):

        message = {}

        week= [1,2,3,4,5]

        id = int(request.data.get(id))


        ProTime = []

         遍历每个时刻
        for x in [8,9,10,11,12,13,14,15,16,17,18]:
            ProMeetTableRaw = models.ProMeetTable.objects.filter(user_id=id,time=x).all()

            week_plan = []

            for table in ProMeetTableRaw:
                week_plan.append(table.week)

             遍历计算出每个时刻空内容的星期 创建一个空包在数据库内
            for week_set  set(week).difference(set(week_plan)):
                models.ProMeetTable.objects.create(week=week_set,time=x,user_id=id,title="")

             根据时刻 将周一到周五全部抽出来
            ProMeetTableSet = models.ProMeetTable.objects.filter(user_id=id,time=x).all().order_by(week)
            data_f = {}
            data_f[time"] = {}:00.format(x)
             ProMeetTableSet:
                data_f[self.type_week(table.week)] = table.title
            ProTime.append(data_f)

             删除所有空字段
            models.ProMeetTable.objects.filter(user_id=id,1)">).all().delete()

        message[code'] = 200
        message[data'] = ProTime


         JsonResponse(message)


     type_time(self,item):
        data = {8: ,15: = data[item]
         res

     type_week(self,item):
        data = {1: return res



# 数据渲染

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