OSCer 都在干嘛？

发布时间：2020-12-17 17:30:21 所属栏目：Python 来源：网络整理

导读：今天PHP站长网 52php.cn把收集自互联网的代码分享给大家，仅供参考。 import requestsimport lxmlfrom lxml import etreedef get_content(url): try: headers = {'User-Agent': 'Mozilla/5.0 (Windows NT 6.2; WOW64; rv:

以下代码由PHP站长网 52php.cn收集自互联网

现在PHP站长网小编把它分享给大家，仅供参考

import requests
import lxml
from lxml import etree
def get_content(url):
    try:
        headers = {'User-Agent': 'Mozilla/5.0 (Windows NT 6.2; WOW64; rv:37.0) Gecko/20100101 Firefox/37.0'}
        r = requests.get(url,headers = headers)
        return '<html>' + r.content.decode('utf-8') + '</html>'
    except Exception as exc:
        #raise exc
        return None


class User(object):
    pass

def parse_content(content):

    if content is None: return []
    try:
        xml = etree.fromstring(content)
        divs= xml.findall('li/div') 
        page_info = []
        for div in divs:
            u = User()
            tweets = div.findall('p')
            if len(tweets) < 2:
                continue
            user_and_text = list(tweets[0].itertext())
            u.name,u.txt =  user_and_text if len(user_and_text) == 2 else [None]*2 

            data_comments = list(tweets[1].itertext())
            u.data,u.commtents,u.client = data_comments if len(data_comments) ==3 else [None]*3
            u.link = tweets[1].xpath('a')[0].get('href') 
            page_info.append(u)
        return page_info
    except Exception as exc:
        raise exc

def test():
    url = "http://www.oschina.net/fetch_tweets?p=40"
    content = get_content(url)
    infos = parse_content(content)
    for u in infos:
	print(u.name)
	print(u.txt)
	print(u.client.split('n')[1].strip() if u.client else u.client)		
        #print(u.name,u.txt)

if __name__ == '__main__':
    test()

以上内容由PHP站长网【52php.cn】收集整理供大家参考研究

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