python通过MD5文件校验来查找重复内容的文件
发布时间:2020-12-17 17:19:14 所属栏目:Python 来源:网络整理
导读:今天PHP站长网 52php.cn把收集自互联网的代码分享给大家,仅供参考。 网上批量下载下来一堆文件,其中有重复的,人工一个一个比对太麻烦~~ 所以想写个Python脚本,通过MD5值校验来比对重复文件,然后把重复的删除掉 #!/
以下代码由PHP站长网 52php.cn收集自互联网 现在PHP站长网小编把它分享给大家,仅供参考
网上批量下载下来一堆文件,其中有重复的,人工一个一个比对太麻烦~~
所以想写个Python脚本,通过MD5值校验来比对重复文件,然后把重复的删除掉 #!/usr/bin/python #encoding=utf-8 #import the modules import os import os.path import sys import hashlib #define the functions def findFile(rootPath,fileSeq,delSeq): dirs = os.listdir(rootPath) #list the directories under the root path for dir in dirs: #traversal all the directories path = rootPath + os.sep + dir #complete the path of current file if os.path.isdir(path): findFile(path,delSeq) #if current file is a directory,recursive the function else: md5Check(path,delSeq) #if not a directory,check the md5 def md5Check(path,delSeq): f = file(path,'rb') #open the file with 'read-only' and 'binary' md5obj = hashlib.md5() md5obj.update(f.read()) #calculate the md5 if md5obj.hexdigest() in fileSeq: delSeq.append(path) #if md5 of current file is in the fileSeq,put the file path into the delSeq else: fileSeq.append(md5obj.hexdigest()) #if not in the fileSeq,put the md5 into the fileSeq f.close() #close the file def delList(delSeq): print 'These files are waiting to be removed:' for delFile in delSeq: print delFile #list the file path in the delSeq #the main program fileSeq = [] delSeq = [] while True: if len(sys.argv) == 1: rootPath = raw_input('Enter the root path: ') #one parameter means no parameter,ask the root path else: rootPath = sys.argv[1] #or get the second parameter as the root path try: findFile(rootPath,delSeq) #try if the root path is valid except(OSError): print 'The root path is invalid. Please enter again. ' del sys.argv[1:] continue #catch the except and delete all invalid parameters break if len(delSeq) == 0 : print 'No duplicate file was found! ' #if no files in delSeq,exit else: delList(delSeq) #or list the delSeq while True: answer = raw_input('Would you want to remove these files? Please answer yes(y) or no(n): ') answer.lower if answer in ('yes','y'): #if "yes" for delFile in delSeq: try: os.remove(delFile) #remove all files in delSeq except(OSError): print 'Warning! "%s" is not existed! ' % delFile continue #ignore the files witch are not existed print 'All duplicate files have been removed! ' break elif answer in ('no','n'): print 'Process has exited without any change! ' break #if "no",do nothing else: print 'Please enter yes(y) or no(n). ' sys.exit() 以上内容由PHP站长网【52php.cn】收集整理供大家参考研究 如果以上内容对您有帮助,欢迎收藏、点赞、推荐、分享。 (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |