用python从多个文件中提取有用信息到一个文件中
发布时间:2020-12-17 17:04:31 所属栏目:Python 来源:网络整理
导读:今天PHP站长网 52php.cn把收集自互联网的代码分享给大家,仅供参考。 f0=open("STAS_FOR_mul_div.txt","r")f1=open("STAS_FOR_nqueen.txt","r")f2=open("STAS_FOR_registers_dis.txt","r")f3=open("STAS_FOR_registers_di
以下代码由PHP站长网 52php.cn收集自互联网 现在PHP站长网小编把它分享给大家,仅供参考 f0=open("STAS_FOR_mul_div.txt","r") f1=open("STAS_FOR_nqueen.txt","r") f2=open("STAS_FOR_registers_dis.txt","r") f3=open("STAS_FOR_registers_dis0.txt","r") f4=open("result.txt","w") dicts={} cnt=0 lines0=f0.readlines() lines1=f1.readlines() lines2=f2.readlines() lines3=f3.readlines() f0.close() f1.close() f2.close() f3.close() for line0 in lines0: if '%' in line0: a=line0.find(':') b=line0[0:a] #if not dicts.hasKey(b): if not b in dicts: dicts[b]=1 cnt=cnt+1 #f4.write(b+'n') for line1 in lines1: if '%' in line1: a=line1.find(':') b=line1[0:a] #if not dicts.has_key(b): if not b in dicts: dicts[b]=1 cnt=cnt+1 #f4.write(b+'n') for line2 in lines2: if '%' in line2: a=line2.find(':') b=line2[0:a] #if not dicts.has_key(b): if not b in dicts: dicts[b]=1 cnt=cnt+1 #f4.write(b+'n') for line3 in lines3: if '%' in line3: a=line3.find(':') b=line3[0:a] #if not dicts.has_key(b): if not b in dicts: dicts[b]=1 cnt=cnt+1 #f4.write(b+'n') for i in range(5): s='STAS_FOR_test'+str(i)+'.txt' f=open(s,'r') lines=f.readlines() f.close() for line in lines: if '%' in line: a=line.find(':') b=line[0:a] if not b in dicts: dicts[b]=1 cnt=cnt+1 #f4.write(b+'n') dicts=sorted(dicts.items(),key=lambda item:item[0],reverse=False) for item in dicts: f4.write(item[0]+'n') f4.write('n'+str(cnt)+'n') f4.close() 以上内容由PHP站长网【52php.cn】收集整理供大家参考研究 如果以上内容对您有帮助,欢迎收藏、点赞、推荐、分享。 (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |