Python3调用微信企业号API发送文本消息代码示例
发布时间:2020-12-17 07:55:23 所属栏目:Python 来源:网络整理
导读:本文主要向大家分享了Python3调用微信企业号API发送文本消息示例的有关代码,具体如下: #!/usr/bin/env python# -*- coding:utf-8 -*-import urllib.requestimport jsonimport sysimport loggingtouser = '@all'agentid = 0corpid = 'wx5aef2da956514535'co
本文主要向大家分享了Python3调用微信企业号API发送文本消息示例的有关代码,具体如下: #!/usr/bin/env python # -*- coding:utf-8 -*- import urllib.request import json import sys import logging touser = '@all' agentid = 0 corpid = 'wx5aef2da956514535' corpsecret = 'Co17m_OPlvE8Q4P2RKKwtq5oIA3p42xGUZEvCHBI8S0' url = 'https://qyapi.weixin.qq.com' subject = sys.argv[2] message = sys.argv[3] logging.basicConfig(level=logging.DEBUG,filename='E:Python_projectScriptsmy.log',format='%(asctime)s - %(levelname)s: %(message)s') class Weixin: def __init__(self,url,corpid,corpsecret): token_url = '%s/cgi-bin/gettoken?corpid=%s&corpsecret=%s' % (url,corpsecret) self.token = json.loads(urllib.request.urlopen(token_url).read().decode())['access_token'] def send_message(self,data): send_url = '%s/cgi-bin/message/send?access_token=%s' % (url,self.token) self.respone = urllib.request.urlopen(urllib.request.Request(url=send_url,data=data)).read() x = json.loads(self.respone.decode())['errcode'] if x == 0: logging.debug('Successfully %s %s' % (subject,message)) return 'Succesfully' else: logging.debug('Failed %s %s' % (subject,message)) return 'Failed' def messages(self,subject,message): values = { "touser": touser,"msgtype": 'text',"agentid": agentid,"text": {'content': subject + message},"safe": 0 } return self.send_message(url,bytes(json.dumps(values),'utf-8')) if __name__ == '__main__': obj = Weixin(url,corpsecret) ret = obj.messages(subject,message) 总结 以上就是本文关于Python3调用微信企业号API发送文本消息代码示例的全部内容,希望对大家有所帮助。感兴趣的朋友可以继续参阅本站:在Python web中实现验证码图片代码分享、python实现人脸识别代码、Python爬虫实例爬取网站搞笑段子等,有什么问题可以随时留言,小编会及时回复大家的。感谢朋友们对本站的支持! (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |