python实现将英文单词表示的数字转换成阿拉伯数字的方法
发布时间:2020-12-16 22:35:23 所属栏目:Python 来源:网络整理
导读:本篇章节讲解python实现将英文单词表示的数字转换成阿拉伯数字的方法。供大家参考研究。具体实现方法如下: import re_known = { 'zero': 0,'one': 1,'two': 2,'three': 3,'four': 4,'five': 5,'six': 6,'seven': 7,'eight': 8,'nine': 9,'ten': 10,
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本篇章节讲解python实现将英文单词表示的数字转换成阿拉伯数字的方法。分享给大家供大家参考。具体实现方法如下:
import re
_known = {
'zero': 0,'one': 1,'two': 2,'three': 3,'four': 4,'five': 5,'six': 6,'seven': 7,'eight': 8,'nine': 9,'ten': 10,'eleven': 11,'twelve': 12,'thirteen': 13,'fourteen': 14,'fifteen': 15,'sixteen': 16,'seventeen': 17,'eighteen': 18,'nineteen': 19,'twenty': 20,'thirty': 30,'forty': 40,'fifty': 50,'sixty': 60,'seventy': 70,'eighty': 80,'ninety': 90
}
def spoken_word_to_number(n):
"""Assume n is a positive integer".
assert _positive_integer_number('nine hundred') == 900
assert spoken_word_to_number('one hundred') == 100
assert spoken_word_to_number('eleven') == 11
assert spoken_word_to_number('twenty two') == 22
assert spoken_word_to_number('thirty-two') == 32
assert spoken_word_to_number('forty two') == 42
assert spoken_word_to_number('two hundred thirty two') == 232
assert spoken_word_to_number('two thirty two') == 232
assert spoken_word_to_number('nineteen hundred eighty nine') == 1989
assert spoken_word_to_number('nineteen eighty nine') == 1989
assert spoken_word_to_number('one thousand nine hundred and eighty nine') == 1989
assert spoken_word_to_number('nine eighty') == 980
assert spoken_word_to_number('nine two') == 92 # wont be able to convert this one
assert spoken_word_to_number('nine thousand nine hundred') == 9900
assert spoken_word_to_number('one thousand nine hundred one') == 1901
"""
n = n.lower().strip()
if n in _known:
return _known[n]
else:
inputWordArr = re.split('[ -]',n)
assert len(inputWordArr) > 1 #all single words are known
#Check the pathological case where hundred is at the end or thousand is at end
if inputWordArr[-1] == 'hundred':
inputWordArr.append('zero')
inputWordArr.append('zero')
if inputWordArr[-1] == 'thousand':
inputWordArr.append('zero')
inputWordArr.append('zero')
inputWordArr.append('zero')
if inputWordArr[0] == 'hundred':
inputWordArr.insert(0,'one')
if inputWordArr[0] == 'thousand':
inputWordArr.insert(0,'one')
inputWordArr = [word for word in inputWordArr if word not in ['and','minus','negative']]
currentPosition = 'unit'
prevPosition = None
output = 0
for word in reversed(inputWordArr):
if currentPosition == 'unit':
number = _known[word]
output += number
if number > 9:
currentPosition = 'hundred'
else:
currentPosition = 'ten'
elif currentPosition == 'ten':
if word != 'hundred':
number = _known[word]
if number < 10:
output += number*10
else:
output += number
#else: nothing special
currentPosition = 'hundred'
elif currentPosition == 'hundred':
if word not in [ 'hundred','thousand']:
number = _known[word]
output += number*100
currentPosition = 'thousand'
elif word == 'thousand':
currentPosition = 'thousand'
else:
currentPosition = 'hundred'
elif currentPosition == 'thousand':
assert word != 'hundred'
if word != 'thousand':
number = _known[word]
output += number*1000
else:
assert "Can't be here" == None
return(output)
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