Python二分查找详解
发布时间:2020-12-16 21:27:44 所属栏目:Python 来源:网络整理
导读:先来看个实例 #!/usr/bin/env python import sys def search2(a,m): low = 0 high = len(a) - 1 while(low = high): mid = (low + high)/2 midval = a[mid] if midval m: low = mid + 1 elif midval m: high = mid - 1 else: print mid return mid print -1
先来看个实例 #!/usr/bin/env python import sys def search2(a,m): low = 0 high = len(a) - 1 while(low <= high): mid = (low + high)/2 midval = a[mid] if midval < m: low = mid + 1 elif midval > m: high = mid - 1 else: print mid return mid print -1 return -1 if __name__ == "__main__": a = [int(i) for i in list(sys.argv[1])] m = int(sys.argv[2]) search2(a,m) 运行: administrator@ubuntu:~/Python$ python test_search2.py 123456789 4 3 注: 1.'__':由于python的类成员都是公有、公开的被存取public,缺少像正统面向对象语言的私有private属性。 Python采用二分查找找出数字的下标 要考虑有重复数字的情况 class Solution(object): def searchRange(self,nums,target): """ :type nums: List[int] :type target: int :rtype: List[int] """ def binary_search(start,end,value): while end>=start: mid = (start+end)//2 print(mid) if nums[mid]>target: end = mid-1 elif nums[mid]<target: start = mid+1 else: if value==-1: if mid-1>=start and nums[mid+value] == target: end = mid+value else: return mid else: if mid+1<=end and nums[mid+value] == target: start = mid+value else: return mid return -1 a=binary_search(0,len(nums)-1,-1) b=binary_search(0,1) return [a,b] a = Solution() l = [2,2] print(a.searchRange(l,2)) 二分算法的定义不在多说了,百度一下就知道(支持国产大笑) import sys source = [1,2,3,4,5,6,7,8,9,10] #must be in order des = int(sys.argv[1]) low = 0 high = len(source) - 1 targetIndex = -1 print "des=",des while low <= high: middle = (low + high)/2 if des == source[middle]: targetIndex = middle break elif des < source[middle]: high = middle -1 print "middle element[index=",middle,",value=",source[middle],"] is bigger than des,continue search from[",low,"to",high,"]" else: low = middle + 1 print "middle element[index=","] is smaller than des,"]" print "search complete,target element's index in source list is ",targetIndex 最后在分享一个 'fileName--BinarySearch.py' src = [] def BinarySearch(low,target,*src): '二分查找' while low <= high: mid = (low + high) // 2 midVal = src[mid] if target < midVal: high = mid - 1 elif target > midVal: low = mid + 1 else: return mid BinarySearch(low,*src) print('Please input 10 number:') for number in range(10): src.append(int(input('Num %d:' % number))) sortList = tuple(src) key = int(input('Please input key:')) location = BinarySearch(0,len(src) - 1,key,*sortList) if location != None: print('Find target at %d' % (location + 1)) else: print('No target!') (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |